Target NEET 2023-2024 Past Paper PDF

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Ö´ÖÞÖÖ¸ü ®ÖÖÆüß †ÃÖÖ ×¾Ö“ÖÖ¸ü Ûú¸üŸÖ ²ÖÃÖÞµÖÖ¯ÖêõÖÖ Ûúºþ®Ö ŸÖ¸üß ²Ö‘Öæ ´ÆüÞÖŸÖ Ûêú»Öê»Öß ÃÖãºþ¾ÖÖŸÖ ´ÆüÞÖ Öê“Ö Öß¾Ö®ÖÖŸÖ µÖ¿ÖþÖß ÆüÖêÞµÖÖ“Ö ¯Ö×Æü»ÖÓ ¯ÖÖ‰ú»Ö †ÃÖŸÖÓ. Mark Group Target NEET-2023-24 (Round-I) Date : 12/01/2024 720 PCB Vijaypath Test Series-Test : 17(55) Time : 03 Hrs. 20 Mins. Physics - 50 Chemistry - 50 Biology - 100 Question Booklet Version Roll Number Question Booklet Sr. No. (Write this number 11 P-11 on your Answer Sheet) Today’s Test Syllabus Physics : Wave Optics RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** Chemistry : Aldehydes, Ketones And Carboxylic Acids Biology : Molecular Basis of Inheritance Next Test Syllabus Date : 14/01/2024 Physics : Dual Nature of Radiation and Matter + Nuclei Chemistry : Solutions Biology : Biotechnology-I + Biotechnology-II PHYSICS 2. Three coherent waves having amplitudes Section : A 12 mm, 6 mm, and 4 mm arrive at a given 1. Assertion : In the figure shown, zero order maxima point with successive phase difference of will lie above the point O. [ NCERT Page-363] /2. Then, the amplitude of the resultant wave is [ NCERT Page-361] 1) 7 mm 2) 10 mm 3) 5 mm 4) 4.8 mm 3. In the Young’s double slit experiment, the angular Reason : Zero order maxima normally means a width of a fringe formed on a distant screen is 1°, point where path difference is zero. the wavelength of light used is 6000 Å. The 1) If both Assertion and Reason are true and the spacing between the slits is [ NCERT Page-363] Reason is correct explanation of the Assertion 2) If both Assertion and Reason are true but 1) 6 × 10–7 m Reason is not the correct explanation of 2) 6.8 × 10–5 m Assertion 3) 3.4 × 10–5 m 3) If Assertion is true, but the Reason is false 4) If Assertion is false but the Reason is true. 4) 3.4 × 10–4 m PCB TEST : 17(55) 1 Date : 12/01/2024 QUESTION BOOKLET VERSION : P-11 4. Two coherent point sources S 1 and S 2 are 8. In a double-slit experiment, instead of taking RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** separated by a small distance d as shown. The slits of equal width, one slit is made twice as fringes obtained on the screen will be wide as the other. Then, in the interference pattern. [ NCERT Page-363] 1) the intensities of both the maxima and the minima increases [ NCERT Page-365] 2) the intensity of the maximum increase and minima has zero intensity 1) points 2) straight lines 3) the intensity of the maxima decreases and that 3) semi-circle 4) concentric circles of minima increases 5. In Young’s double slit experiment,  = 6000 Å 4) the intensity of the maxima decreases and the Path difference corresponding to 4th maxima minima has zero intensity will be equal to [ NCERT Page-363] 1) 1500 Å 2) 3000Å 9. Two beams of light having intensities I and 3) 12000Å 4) 24000Å 4I interfere to produce a fringe pattern on a 6. Assertion : Thin films such as soap bubbles or a screen. The phase between the beams is /2 thin layer of oil on water show beautiful colours at point A and  at point B. Then, the when illuminated by monochromatic light. difference between the resultant intensities at Reason : The colours are obtained by the A and B is [ NCERT Page-362] dispersion of light. [ NCERT Page-366] 1) If both Assertion and Reason are True and 1) 2I 2) 4I Reason is a correct explanation of Assertion. 3) 5I 4) 7I 2) If both Assertion and Reason are True but Reason is not the correct explanation of 10. In YDSE, find the thickness of a glass slab Assertion. ( = 1.5) which should be placed before the 3) If the Assertion is True but the Reason is False. upper slit S1 so that the central maximum now 4) If both Assertion and Reason are False. lies at a point where 5th bright fringe was lying 7. One of the two slits in YDSE is painted over, earlier (before inserting the slab). Wavelength so that it transmits only light waves having of light used is 5000 Å. [ NCERT Page-364] intensity half of the intensity of the light 1) 5 × 10–6 m 2) 3 × 10–6 m waves through the other slit. As a result of this [ NCERT Page-363] 3) 10 × 10–6 m 4) 5 × 10–5 m 1) fringe pattern disappears 11. By Huygen’s wave theory of light, we cannot 2) bright fringes become brighten and dark ones explain the phenomenon of [ NCERT Page-355] become darker 3) dark and bright fringes get fainter 1) Interference 2) Diffraction 4) dark fringes get brighter and bright fringes 3) Photoelectric effect 4) Refraction get darker Space For Rough Work PCB TEST : 17(55) 2 Date : 12/01/2024 QUESTION BOOKLET VERSION : P-11 12. A plane wavefront travelling 15. In YDSE, the wavelength of red light is RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** 7800 Å and that of blue light is 5200 Å. The in a straight line in vacuum value of n for which nth bright band due to encounters a medium red light coincides with (n + 1)th bright band of refractive index µ. At P, due to blue light, is [ NCERT Page-364] the shape of the wavefront 1) 1 2) 2 is [ NCERT Page-357] 3) 3 4) 4 16. In Young’s double slit experiment, the seventh maximum with wavelength  1 is at a distance d 1 from central maxima and the same 1) 2) 3) 4) maximum with wavelength  2 is at a distance d2. Then d1/d2. [ NCERT Page-364] 13. If ratio of amplitude of two interfering 1 2 source is 3 : 5. Then ratio of intensity of 1)  2)  2 1 maxima and minima in interference pattern will be [ NCERT Page-362]  12  22 3) 2 4) 2 1) 25 : 16 2) 5 : 3 2 1 3) 16 : 1 4) 25 : 9 17. Fringe width observed in the Young’s double slit experiment is . If the frequency 14. In Young’s experiment of the source is doubled, the fringe width monochromatic light will [ NCERT Page-364] is used to illuminate 1) remain  2) become /2 the two slits A and B. 3) become 2 4) remain 3/2 Interference fringes are observed on a 18. The correct curve between fringe with () and distance between the slits (d) in Young’s screen placed in front double slit experiment is [ NCERT Page-364] of the slits. Now, if a thin glass plate is placed normally in the path of the beam coming from the slit A, then [ NCERT Page-366] 1) 2) 1) the fringes will disappear 2) the fringe width will increase 3) the fringe width will decrease 3) 4) 4) there will be no change in fringe width but fringe pattern shifts. Space For Rough Work PCB TEST : 17(55) 3 Date : 12/01/2024 QUESTION BOOKLET VERSION : P-11 19. In Young’s double-slit experiment, the 23. If the distance between the first maxima and RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** intensity at a point where path difference is fifth minima of a double slit pattern is 7 mm /6 is I’. If I0 denotes the maximum intensity, and the slits are separated by 0.15 mm with then I’/I0 is equal to [ NCERT Page-362] the screen 50 cm from the slits, then wavelength 1 of the light used is [ NCERT Page-364] 3 1) 2) 1) 600 nm 2) 525 nm 4 2 3) 467 nm 4) 420 nm 3 1 3) 4) 24. Two point source separated 2 2 20. Assertion : When a thin transparent sheet is by d = 5 m emit light placed in front of both the slits of Young’s of wavelength  = 2 m experiment the fringe width will increase. in phase. A circular Reason : In Young’s experiment the fringe width wire of radius 20 m is is directly proportional to the wavelength of the placed around the source source used. [ NCERT Page-364] as shown in figure. 1) If both Assertion and Reason are True and [ NCERT Page-364] Reason is a correct explanation of Assertion. 2) If both Assertion and Reason are True but Reason 1) Points A and B are dark and points C and D is not the correct explanation of Assertion. are bright. 3) If the Assertion is True but the Reason is False. 2) Point A and B are bright and point C and D 4) IfAssertion is false and Reason is true. are dark. 21. In Young’s double slit experiment, the intensity at a point is (1/4) of maximum intensity. Angular 3) Points A and C are dark and point B and D position of this point is [ NCERT Page-362] are bright. 1) sin–1 (/d) 2) sin–1 (/2d) 4) Points A and C are bright and points B and D 3) sin–1 (/3d) 4) sin–1 (/4d) are dark. 22. In Young’s double slit experiment one of the slits is wider than other, so that amplitude of the light 25. Two coherent light sources P from one slit is double of that from other slit. If and Q each of wavelength  Im be the maximum intensity, the resultant are separated by a distance 3 intensity when they interfere at phase difference as shown. The maximum is given by [ NCERT Page-363] number of minima formed on Im Im   line AB which rns from – 1) (4  5cos ) 2)  1  2 cos 2  to + is [ NCERT Page-364] 9 3 2 1) 2 2) 4 Im   Im   3)  1  4 cos 2  4)  1  8 cos 2  3) 6 4) 8 5 2 9 2 Space For Rough Work PCB TEST : 17(55) 4 Date : 12/01/2024 QUESTION BOOKLET VERSION : P-11 26. In a Young’s double slit experiment, the ratio of 31. Plane polarised light is passed through a polaroid. RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** the slit’s width is 4 : 1. The ratio of the intensity on viewing through the polariod we find that of maxima to minima, close to the central fringe when the polariod is given one complete rotation on the screen, will be [ NCERT Page-362] about the direction of the light, one of the following is observed. [ NCERT Page-378] 1) ( 3  1)4 : 16 2) 9 : 1 1) The intensity of light gradually decreases to zero and remains at zero 3) 4 : 1 4) 25 : 9 2) The intensity of light gradually increases to a 27. In a YDSE apparatus, d = 2 mm,  = 600 nm, maximum and remains at maximum D = 1 m The slits individually produce 3) There is no change in intensity same intensity on the screen. Find the position 4) The intensity of light is twice maximum and of point from central bright fringe where twice zero intensity is 3/4 times of the maximum 32. At what angle should an unpolarised beam intensity on screen [ NCERT Page-364] be incident on a crystal of   3 , so that 1) 0.01 mm 2) 13 × 10–4 mm reflected beam is polarised [ NCERT Page-380] 3) 0.05 mm 4) 1.5 × 10–4 mm 1) 45° 2) 60° 3) 90° 4) 0° 28. The first diffraction minimum due to a single slit 33. Suppose  is the polarisation angle for a diffraction is at  = 30°, for a light of wavelength transparent medium and the speed of light in 5000 Å. The width of slit is [ NCERT Page-368] that medium is v. Then according to Brewster 1) 1 × 10–4 cm 2) 2.0 × 10–4 cm law [ NCERT Page-381] 3) 2.5 × 10–4 cm 4) 5 × 10–4 cm 1  v  1)   cot   2)   cos 1 v 29. Light of wavelength 6000Å is incident c normally on a slit of width 24 × 10–5 cm. Find 3)   sin 1 ( v) 4)   cosec 1 ( v) out the angular position of second minimum 34. Assertion : No interference pattern is detected from central maximum? [ NCERT Page-368] when two coherent sources are infinitely close 1) 30° 2) 37° to each other. [ NCERT Page-378] Reason : The fringe width is inversely proportional 3) 45° 4) 60° to the distance between the two slits. 30. In a single slit diffraction experiment 1) If both assertion and reason are true and the first minimum for  1 = 660 nm coincides reason is the correct explanation of the assertion. with first maxima for wavelength  2. 2) If both assertion and reason are true and the Calculate  2. [ NCERT Page-368] reason is not the correct explanation of the assertion. 1) 220 nm 2) 520 nm 3) If assertion is true but reason is false. 3) 330 nm 4) 440 nm 4) If both assertion and reason are false. Space For Rough Work PCB TEST : 17(55) 5 Date : 12/01/2024 QUESTION BOOKLET VERSION : P-11 35. When two incoherent light sources each of 39. The main difference between the phenomena RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** maximum intensity I fall on a surface, maximum of interference and diffraction is that resultant intensity is [ NCERT Page-362] [ NCERT Page-367] 1) I 2) 2I 1) Diffraction is due to interaction of light from 3) 4I 4) 8I the same wave front, whereas interference is the Section : B interaction of waves from two separate sources. 36. Statement 1 : Interference phenomena is based 2) Diffraction is due to superposition of light from upon conservation of energy principle the same wavefront, whereas interference is due to two waves derived from the same source. Statement 2 : All the bright fringes are of the same intensity in YDSE. 3) Diffraction is due to two waves derived from the same source, while interference is [ NCERT Page-362] superposition of light from same sources. 1) Both statement-1 and statement-2 are True. 4) In both diffraction and interference, number 2) Both statement-1 and statement-2 are False of coherent sources is two. 3) Statement-1 is True but Statement-2 is False 40. In YDSE, Bichromatic light of wavelength 4) Statement-1 is False but Statement-2 is True  1 = 6000Å and  2 = 7000Å is used Find for 37. A diffraction pattern is obtained using a beam bright fringe minimum order of  1 which of red light. If the red light is replaced by the overlapped with  2 [ NCERT Page-364] blue light, then [ NCERT Page-371] 1) 7th bright fringe of 1 is overlapped with 6th 1) the diffraction pattern remains unchanged bright fringe of 2. 2) diffraction bands become narrower and 2) 4th bright fringe of 1 is overlapped with 3th crowded together. bright fringe of 2. 3) bands become broader and farther apart 3) 4th bright fringe of 1 is overlapped with 2th 4) bands disappear bright fringe of 2. 38. In single slit diffraction, light of wavelength 4) None of these 5000 Å is used. Distance of screen from slit 41. An YDSE is performed with bi-chromatic light is 3 m. Distance between 2 nd dark and 1 st (5500 Å and 6000 Å) for d = 2 mm and D = 1 m dark fringe is 2 mm. The width of the slit is Distance for first complete maxima from central [ NCERT Page-368] maxima on the screen, is [ NCERT Page-363] 1) 0.20 mm 2) 0.75 mm 1) 1.1 mm 2) 2.2 mm 3) 0.50 mm 4) 0.10 mm 3) 3.3 mm 4) 4.4 mm Space For Rough Work PCB TEST : 17(55) 6 Date : 12/01/2024 QUESTION BOOKLET VERSION : P-11 42. The distance between two coherent sources 48. n identical waves each of intensity I0 interfere RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** RCC** is 0.1 mm. The fringe-width on a screen with each other. The ratio of maximum 1.2 m away from the source is 6.0 mm. The intensities if the interference is (i) coherent wavelength of light used is [ NCERT Page-364] and (ii) incoherent is [ NCERT Page-362] 1) 4000 Å 2) 5000 Å 1 3) 6000 Å 4) 7200 Å 1) n2 2) 43. The angular fringe width does not depend n upon [ NCERT Page-362] 1 1) Wavelength () 3) 4) n 2) Distance between slits (d) n2 3) Distance between slits and screen 49. The colours are characterised by which of 4) (d) Ratio /d following character of light. [ NCERT Page-354] 44. Young’s double-slit experiment is carried out by using green, red and blue light, one colour at a 1) Frequency time. The fringe widths recorded are G , R and 2) Amplitude B respectively. Then [ NCERT Page-364] 3) Wavelength 1) G > B > R 2) B > G > R 3) R > B > G 4) R > G > B 4) Velocity 45. If two waves represented by y 1 = 4 sin t 50. Assertion : In the YDSE apparatus shown in and y2 = 3 sin (t + /3) interfere at a point, d the amplitude of the resulting wave will be figure d