NEET (UG) 2024 Full Syllabus Test 9 PDF
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New Light Institute
2024
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Summary
This is a past paper for the 2024 NEET (UG) exam. It covers questions from Physics, Chemistry, and Biology and is part of the New Light Test Series.
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Test ID : 909 FST : 09 DURATION : 200 Minutes DATE : 18-Aug-2024 MARKS : 720...
Test ID : 909 FST : 09 DURATION : 200 Minutes DATE : 18-Aug-2024 MARKS : 720 Topic Covered Physics : FULL SYLLABUS Chemistry : FULL SYLLABUS Biology : FULL SYLLABUS (Do not open this Test Booklet until you are asked to do so.) Please read the instructions carefully : The Test pattern of NEET (UG)-2024 comprises of two Sections. Each subject will consist of two sections. Section A will consist of 35 Questions and Section B will have 15 questions, out of these 15 Questions, candidates can choose to attempt any 10 Questions. The pattern for the NEET (UG)-2024 Examination for admission in the Session 2024-25 is as follows: The important points to note: I. Each question carries 04 (four) marks and, for each correct answer candidate will get 04 (four) marks. II. For each incorrect answer, 01(one) mark will be deducted from the total score. III. To answer a question, the candidate has to find, for each question, the correct answer/ best option. IV. However, after the process of the challenge of key, if more than one option is found to be correct then all/any one of the multiple correct/best options marked will be given four marks (+4). Any incorrect option marked will be given minus one mark (-1). Unanswered/Unattempted questions will be given no marks. In case, a question is dropped/ ignored, all candidates will be given four marks (+4) irrespective of the fact whether the question has been attempted or not attempted by the candidate. Name of the Student (In CAPITALS) : _____________________________________________________________ Candidate ID : _________________________________________________________________________________ Candidate Signature : _____________________________ Invigilator's Signature : _______________________ All India Full Syllabus Test–09 [Paper] CRACK NEET 2025 /18-Aug-2024 INSTRUCTION The candidates should ensure that the Answer Sheet is not folded. Do not make any stray marks on the Answer Sheet. Do not write your roll no. anywhere else except in the specified space in the Test Booklet/Answer Sheet. Before attempting the question paper ensure that it contains all the pages and no question is missing. Each candidate must show on demand his/her Admission Card to the Invigilator. If any student is found to have occupied the seat of another student, both the students shall be removed from the examination and shall have to accept any other penalty imposed upon them. No candidate, without special permission of the Superintendent or Invigilator, would leave his/her seat. The candidates should not leave the Examination Hall without handing over their Answer Sheet to the Invigilator on duty and sign the Attendance Sheet twice. Cases where a candidate has not signed the Attendance Sheet second time will be deemed not to have handed over Answer Sheet and dealt with as an unfair means case. Use of Electronic/Manual Calculator is prohibited. The candidates are governed by all Rules and Regulations of the Board with regard to their conduct in the Examination Hall. All cases of unfair means will be dealt with as per Rules and Regulations of the Board. The candidates will write the Correct Test ID Code as given in the Test Booklet/Answer Sheet in the Attendance Sheet. Key Points of New Light Test Series : Rapid Fire Revision of all tests Live Classes available on "New LIght Institute" Channel ( ) before the scheduled test. Video of all tests' solution available on "New Light Institute" App. Chat support 24×7 available for the students on "New Light Institute" App. Test results are regularly sent to the parents and students. For lattest update on NEET, PDF sheets, other examinations and class schedule. Please Subscribe our – Telegram Channel - @NewLightInstituteKanpur Youtube Channel - New Light Institute For Today's Paper Discussion - Scan the QR code - Youtube Channel Link : https://www.youtube.com/@newlightprayaas2583 Youtube Channel Name : New Light Prayaas NLI / 2 All India Full Syllabus Test–09 [Paper] CRACK NEET 2025 /18-Aug-2024 TOPIC : Full Syllabus ¼[k.M -A½ (SECTION-A) lHkh 35 iz'u vfuok;Z gSa Attempt All 35 Questions 1. 2 izfrjks/k dh ,d dqaMyh ls xqtjus okyk pqca dh; 1. Magnetic flux passing through a coil of resistance 2 is as shown in figure. match the following two ¶yDl fp= esa fn[kk;k x;k gS A fuEufyf[kr nks columns. In column II all physical quantities are LraHkksa dk feyku djsaA dkWye AA esa lHkh HkkSfrd in SI units. ek=k,a SI bdkb;ksa eas gSaA Column - I Column - II dkWye -I dkWye - II A. Induced emf produced P. 4 A. izsfjr fo|q r okgd cy P. 4 mRiUu gq vk B. Induced current Q. 1 B. iz sfjr /kjk Q. 1 C. Charge flow in 2s R. 8 C. 2 lsd.M esa vkos'k dk R. 8 D. Heat generation in 2s S. 2 iz o kg (1) A-S, B-Q, C-S, D-P D. 2 lsd.M eas mRiUu Å"ek S. 2 (1) A-S, B-Q, C-S, D-P (2) A-Q, B-R, C-P, D-S (2) A-Q, B-R, C-P, D-S (3) A-P, B-Q, C-R, D-S (3) A-P, B-Q, C-R, D-S (4) A-R, B-Q, C-S, D-P (4) A-R, B-Q, C-S, D-P 2. ,d gh inkFkZ ds cus nks xksyksa dh f=T;k r vkSj 4 r 2. Two spheres of the same material have radii r and gS vkS j rkieku 2T0 vkSj T0 gSA xksyksa dh fofdj.k 4r and temperature 2T 0 and T 0 respectively. The ÅtkZ vksa dk vuq ikr gksxkA ratio of rate of radiation of energy by the spheres is : (1) 1 : 1 (1) 1 : 1 (2) 1 : 2 (2) 1 : 2 (3) 2 : 1 (3) 2 : 1 (4) 3 : 1 (4) 3 : 1 3. ,d iz f rpq E cdh; inkFkZ ¼lHkh iz f rdks a dk viuk 3. The incorrect relation for a diamagnetic material lkekU; vFkZ gS vkSj ε ,d NksVh /kukRed la[ ;k (all the symbols carry their usual meaning and ε gSA½ ds fy, xyr laca/k gSA is a small positive number) is : (1) 0 (1) 0 (2) 0 r 1 (2) 0 r 1 (3) 1 x 0 (3) 1 x 0 (4) 1 r 1 (4) 1 r 1 NLI / 3 All India Full Syllabus Test–09 [Paper] CRACK NEET 2025 /18-Aug-2024 4. vkn'kZ xSl ,d iz Øe esa bl izdkj ifjofrZr gksrs gS 4. An ideal gas is taken through a process in which ftlls nkc P rFkk vk;ru V lehdj.k PV = fu;rkad the pressure and the volume are changed ds vuq lkj ifjofrZRk gks jgk gS] rks izØe ds fy, according to the equation P = k.V. Molar heat eksyj fof'k"V Å"ek gksxh % capacity of the gas for the process is : (1) C = Cv + R (1) C = Cv + R (2) C = Cv + R/2 (2) C = Cv + R/2 (3) C = Cv – R/2 (3) C = Cv – R/2 (4) C = Cv + 2R. (4) C = Cv + 2R. 5. ;fn nks Lofj= f}Hkq t ftudh vko`fÙk 450 Hz rFkk 5. Two tuning forks have frequencies 450 Hz and 454 454 Hz gSA budks ,d lkFk ctkus ij nks yxkrkj Hz respectively. On sounding these forks together, vf/kdre rhoz rkvksa ds chp dk le;kUrjky gksxk % the time interval between successive maximum intensities will be : (1) 1/4 sec (1) 1/4 sec (2) 1/2 sec (2) 1/2 sec (3) 1 sec (3) 1 sec (4) 2 sec. (4) 2 sec. 6. uhps nks dFku fn, x, gS % 6. Given below are two statements : dFku I : xSl ds v.kq vksa dk vkSlr eqDr iFk vk.kfod Statement I : The mean free path of gas molecules O;kl ds oxZ ds O;q RØekuq ikrh gksrk gSA is inversely proportional to square of molecular diameter. dFku II : xSLk dh vkSlr xfrt ÅtkZ xSl ds ije rkieku ds lekuq ikrh gksrh gSA Statement II : Average kinetic energy of gas molecules is directly proportional to absolute mijksDr dFkuksa ds lanHkZ esa uhps fn, x, fodYiksa esa temperature of gas. lokZf/kd mi;q Dr mRrj dk p;u dhft, % In the light of the above statements, choose the most appropriate answer from the options given (1) dFku I vkSj dFku II nksuksa xyr gSA below : (2) dFku I lgh gS ysfdu dFku II xyr gSA (1) Both Statement I and Statement II are incorrect (3) dFku I xyr gS ysfdu dFku II lgh gSA (2) Statement I is correct but Statement II is incorrect (3) Statement I is incorrect but Statement II is correct (4) dFku I vkSj dFku II nksuksa lgh gSA (4) Both Statement I and Statement II are correct. 7. ';ku ekè;e esa xksyh dh lhekUr osx% 7. The terminal velocity of a sphere moving through a viscous medium is : (1) xksyh dh f=T;k ds lekuqikrh gksrh gS (1) Directly proportional to the radius of the sphere (2) xksyh dh f=T;k ds O;qRØekuqikrh gsrh gS (2) Inversely proportional to the radius of the sphere (3) xksyh dh f=T;k ds oxZ ds lekuqikrh gksrh gS (3) Directly proportional to the square of the radius of sphere (4) xksyh dh f=T;k ds oxZ ds O;qRØekuqikrh gksrh gS (4) Inversely proportional to the square of the radius of sphere NLI / 4 All India Full Syllabus Test–09 [Paper] CRACK NEET 2025 /18-Aug-2024 8. fp=kuqlkj 15 cm dk ,d leksÙky ysl a chp ls nks 8. An equiconvex lens of focal length 15 cm is cut cjkcj Hkkxksa esa dkVk tkrk gS A iz R ;s d Hkkx dh into two halves as shown in figure. What is the focal length of each part : Qksdl nwjh gksx h% (1) 15 cm (1) 15 cm (2) 30 cm (2) 30 cm (3) 45 cm (3) 45 cm (4) 60 cm (4) 60 cm 9. ,d 3.0 cm dh oLrq 14 cm nwjh ij j[ks 21 cm 9. An object of size 3.0 cm is placed 14 cm in front of Qksdl nwjh okys vory ysal ds lkeus j[kh gq;h gSA a concave lens of focal length 21 cm. Describe at ysl a }kjk izfrfcEc cusxk\ D;k gksxk tc oLrq ysal the image produced by the long lens : ls nwj tk;sxh% (1) –5.4 cm, 3.8 cm (1) –5.4 cm, 3.8 cm (2) –6.4 cm, 2.8 cm (2) –6.4 cm, 2.8 cm (3) –7.4 cm, 3.8 cm (3) –7.4 cm, 3.8 cm (4) –8.4 cm, 1.8 cm (4) –8.4 cm, 1.8 cm 10. [kxksyh; nwjn'khZ dh vko/kZu {kerk 5 gS ftuesa nks 10. An astronomical telescope having magnifying irys ysal 24 cm nwj j[ks gS ysal dh Qksdl nwjh power of 5 consists of two thin lenses 24 cm apart. gks x h% Find the focal length of the lenses : (1) 5 cm, 10 cm (1) 5 cm, 10 cm (2) 10 cm, 4 cm (2) 10 cm, 4 cm (3) 15 cm, 5 cm (3) 15 cm, 5 cm (4) 20 cm, 4 cm (4) 20 cm, 4 cm 11. ,d vYQk d.k ftldk nzO ;eku m ,oa ,d iz ksVku 11. An -particle of mass m and a proton of mass mp ft l d k nzO; eku mp dks leku foHkokUrj }kjk Rofjr are accelerated through the same potential fd;k tkrk gS A bysDVªku vkSj iz ksVku dh Mh&czksxyh difference. The ratio of the de Broglie wavelength rjaxnSè;Z dk vuqikr gSA associated with an -particle to that associated with proton is : (1) 1 (1) 1 (2) 1/4 (2) 1/4 (3) 4/1 (3) 4/1 (4) 1/ 2 2 (4) 1/ 2 2 12. ;ax ds f}fNnz iz;ksx esa fNnzkas ds chp dh nwjh 0.2 12. In Young’s double slits experiment carried out with mm vkSj insZ vkSj fNnzksa ds chp dh nwjh 2 m gSA ;fn light of wavelength 5000A, the distance between iz dk'k dh rjaxnS è;Z 5000A gks rks rhljh nhIr fÝUt the slits is 0.2mm and the screen is at 2 meter dh dsUnz ls nwjh gS% from the slits. Position of 3rd maximum from centre of screen is - (1) 1.5 cm (1) 1.5 cm (2) 5 cm (2) 5 cm (3) 2 cm (3) 2 cm (4) 6 cm (4) 6 cm NLI / 5 All India Full Syllabus Test–09 [Paper] CRACK NEET 2025 /18-Aug-2024 13. cks gj ds gkbMªk s t u ijek.kq es a ,d bys DVªk Wu dk 13. What is the angular momentum of an electron in dks.kh; lao sx D;k gksx k] ftldh ÅtkZ –0.544 eV Bohr's hydrogen atom whose energy is –0.544 eV: gS A h (1) h (1) 2h 2h (2) (2) 7h 7h (3) (3) 2 2 5h 5h (4) (4) 2 2 14. fojkekoLFkk esa 'M' nzO;eku dk ,d d.k nks nzO;ekuksa 14. Particle of mass 'M' at rest breaks into two particles M 2M M 2M rFkk esa foHkDr gks tkrk gS A rks mudh of masses and. Find the ratio of their 3 3 3 3 Mh&czksxyh rajxnSè ;Z dk vuqikr gS % de-Broglie wavelengths : (1) 1 : 2 (1) 1 : 2 (2) 1 : 1 (2) 1 : 1 (3) 2 : 1 (3) 2 : 1 (4) 2 : 3 (4) 2 : 3 15. v/kZpkyd dh fo|qr pkydrk c ΔE ? (1) CH4(g) + O2(g) CO2(g) + H2O(l) (1) CH4(g) + O2(g) CO2(g) + H2O(l) (2) 2CO(g) + O2 2CO2(g) (2) 2CO(g) + O2 2CO2(g) (3) H2(g) + Br2(g) 2HBr(g) (3) H2(g) + Br2(g) 2HBr(g) (4) mijksDr esa ls dksbZ ugha (4) None of these 95. dkS u lk ,Ydksg y R–Mg–X ds lkFk lcls rhoz 95. Which alcohol will react fastest with R–Mg–X: vfHkfØ;k djs x k : (1) Sec–butyl alcohol (1) f}rh;d C;wVkby ,Ydksgy (2) tert – butyl alcohol (2) r`rh;d C;wVkby ,Ydksgy (3) Isobutyl alcohol (3) vkblks C;wVkby ,Ydksgy (4) R–MgX ds fy, lHkh dh nj leku gksxh (4) All will have equal rate for R–MgX: NLI / 25