photo.jpg

## For gases, no. of moles = given vol [v] / molar mass [v] In general, Vm = 22.40 = 22400 ml = 22400 cm³ = 22.4 dm³ =22400 cc | | | | |---|---|---| | atom | x NA | + Molar mass | | molecules | x NA | + Molar mass | | ions | x NA | + Molar mass | | electrons | | | | |...

## For gases, no. of moles = given vol [v] / molar mass [v] In general, Vm = 22.40 = 22400 ml = 22400 cm³ = 22.4 dm³ =22400 cc | | | | |---|---|---| | atom | x NA | + Molar mass | | molecules | x NA | + Molar mass | | ions | x NA | + Molar mass | | electrons | | | | | | | |---|---|---| | particles | x NA | x Molar mass | | | | | |---|---|---| | | | | | | | | | | | | | | x (molar vol / vol of gas) | | ### Ideal gas equation **PV = nRT** Where, R = 8.314 = 25 JK¹ mol⁻¹ or 3 * When, P = Pascal / Nm⁻² V = m³ * When, P = atm / bar V = l OR R = 2 Cal mol⁻¹ k⁻¹ for in thermodynamics.