Aspirin C9H8O4 is prepared by the acetylation of salicylic acid, C7H6O3, according to the following equation: C7H6O3 + (CH3CO)2O → C9H8O4 + CH3COOH.

Understand the Problem

The question is discussing the preparation of Aspirin through the process of acetylating salicylic acid, and it provides a chemical equation that represents this reaction.

Answer

Aspirin (C9H8O4) is prepared from C7H6O3 + (CH3CO)2O.

Aspirin (C9H8O4) is prepared by the acetylation of salicylic acid (C7H6O3) with acetic anhydride ((CH3CO)2O).

Answer for screen readers

Aspirin (C9H8O4) is prepared by the acetylation of salicylic acid (C7H6O3) with acetic anhydride ((CH3CO)2O).

More Information

The reaction typically uses acetic anhydride instead of acetic acid as it reacts more easily and produces fewer side products.

Tips

A common mistake is confusing acetic anhydride (C4H6O3) with acetic acid (CH3COOH); both are related but acetic anhydride is the correct reagent for this synthesis.

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