Aspirin C9H8O4 is prepared by the acetylation of salicylic acid, C7H6O3, according to the following equation: C7H6O3 + (CH3CO)2O → C9H8O4 + CH3COOH.
Understand the Problem
The question is discussing the preparation of Aspirin through the process of acetylating salicylic acid, and it provides a chemical equation that represents this reaction.
Answer
Aspirin (C9H8O4) is prepared from C7H6O3 + (CH3CO)2O.
Aspirin (C9H8O4) is prepared by the acetylation of salicylic acid (C7H6O3) with acetic anhydride ((CH3CO)2O).
Answer for screen readers
Aspirin (C9H8O4) is prepared by the acetylation of salicylic acid (C7H6O3) with acetic anhydride ((CH3CO)2O).
More Information
The reaction typically uses acetic anhydride instead of acetic acid as it reacts more easily and produces fewer side products.
Tips
A common mistake is confusing acetic anhydride (C4H6O3) with acetic acid (CH3COOH); both are related but acetic anhydride is the correct reagent for this synthesis.
Sources
- Aspirin C9H8O4 is synthesized by the reaction of salicylic acid - wyzant.com
- Aspirin, C9H8O4, is prepared by the acetylation of salicylic acid - infinitylearn.com
- Aspirin can be made in the laboratory by reacting acetic anhydrid - pearson.com
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