Chemistry Past Paper PDF
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Uploaded by ProlificAgate1715
Universidad de Monterrey
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This document contains a chemistry past paper with multiple-choice and open-ended questions focusing on electronic configuration and chemical bonds. The questions cover topics such as covalent, ionic, and metallic bonding, along with the octet rule and Pauli Exclusion Principle. This past paper is suitable for secondary school level students.
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## Topics 1.4 Electronic Configuration and 1.5 Types of chemical bonds ### Section I. Multiple Choice Questions **Instructions:** Identify and underline the correct answer. (2 points each, 20 points in total) 1. Which type of bond is formed when aluminum (Al) is combined with oxygen (O)? - A)...
## Topics 1.4 Electronic Configuration and 1.5 Types of chemical bonds ### Section I. Multiple Choice Questions **Instructions:** Identify and underline the correct answer. (2 points each, 20 points in total) 1. Which type of bond is formed when aluminum (Al) is combined with oxygen (O)? - A) Covalent - B) Metallic - C) Ionic - D) Amorphous 2. After constructing the electron configuration for fluorine (F) with atomic number (Z=9), and according to Pauli's exclusion principle, we can conclude that: - A) 2 or 3 electrons with opposite spin may occupy the same orbital. - B) 3 electrons with the same spin may occupy the same orbital. - C) only 2 electrons may occupy an orbital and they must have opposite spin. - D) 3 electrons with opposite spin may occupy the same orbital. 3. State one characteristic of covalent bonds. - A) Sharing of electrons - B) Transferring of electrons - C) Formed between two metals - D) Formed between one metal and one non-metal 4. The sublevel or subshell that contains one orbital is: - A) p - B) s - C) d - D) f 5. Identify the element which the following Lewis structure belongs to: - A) Hydrogen - B) Fluorine - C) Carbon - D) Neon 6. The information we can obtain from the element with the following electron distribution is: - 1s<sup>2</sup> 2s<sup>2</sup> 2p<sup>2</sup> 2p<sup>2</sup> 2p<sup>2</sup> - I. It is located in Group IV A. - II. The name of the element is Calcium (Ca). - III. It is located in Period 4. - IV. It is classified as a representative element. - A) Only II is correct. - B) Only I, II, and IV are correct. - C) Only II and III are correct. - D) Only I and IV are correct. 7. The type of chemical bond between nitrogen (N) and oxygen (O) is: - A) Metallic - B) Covalent - C) Amorphous - D) Ionic 8. The electron configuration of sulfur (S) is: - A) 1s<sup>2</sup>, 2s<sup>2</sup>, 2p<sup>6</sup>, 3s<sup>2</sup>, 3p<sup>6</sup>, 4s<sup>2</sup> - B) 1s<sup>2</sup>, 2s<sup>2</sup>, 2p<sup>6</sup> 3s<sup>2</sup>, 3p<sup>4</sup> - C) 1s<sup>2</sup>, 2p<sup>6</sup>, 3s<sup>2</sup>, 3p<sup>6</sup> - D) 1s<sup>2</sup>, 2s<sup>2</sup>, 2p<sup>6</sup>, 3s<sup>2</sup>, 3d<sup>4</sup> 9. Which pair of elements is more likely to form an ionic compound? - I. Calcium and oxygen - II. Potassium and bromine - III. Sodium and magnesium - IV. Aluminum and sodium - A) Only I y ll - B) Only III - C) Only I, II and IV - D) Only I y IV 10. Identify the true statement about the element whose electron distribution is: - 1s<sup>2</sup> 2s<sup>2</sup> 2p<sup>2</sup> 2p<sup>2</sup> 2p<sup>2</sup> 3s<sup>2</sup> 3p<sup>1</sup> 3p<sup>1</sup> 3p<sup>1</sup> - A) The element is phosphorous (P), with 5 valence electrons. - B) The element is phosphorous (P), with 3 valence electrons. - C) The element is sulfur (S) and it is located in period 3. - D) The element is silicon (Si) and has 5 valence electrons. ### Section III. Open questions **Instructions:** Answer the questions clearly in the space provided. (10 points) 1. Describe the octet rule. (3 points) - Describe: Give a detailed account. - Each element should contain 8 electrons to be complete. 2. Describe the Pauli Exclusion Principle. (3 points)  - Describe: Give a detailed account - Electrons must spread out before putting up with another one. 3. State the formula for the following compounds (4 points): - a) calcium chloride - b) aluminum sulfite. - State: Give a specific name, value or other brief answer without explanation or calculation. - CaCl<sub>2</sub>  - Al<sub>2</sub>(SO<sub>3</sub>)<sub>3</sub> "This is my own work and was carried out in strict adherence to the honor code; any text or"