What will be the output? int a = 1, b = 10; while(a < b) { b = 2; a += 2; } printf("%d %d", a, b);
Understand the Problem
The question is asking for the output of a given piece of C code that involves a loop and prints the values of two variables after running the loop. We need to analyze the code to determine what values will be printed for 'a' and 'b'.
Answer
3 2
Answer for screen readers
The final output will be 3 2
.
Steps to Solve
- Initialize Variables Start with the initial values:
- $a = 1$
- $b = 10$
- Evaluate the While Condition The condition for the loop is $a < b$:
- At this point, $1 < 10$ is true, so we enter the loop.
- Enter the Loop Inside the loop, we perform the following operations:
- Set $b = 2$.
- Update $a$: $a = a + 2$. Thus, $a$ becomes $1 + 2 = 3$.
- Check the Condition Again Return to the while condition:
- Now, $3 < 2$ is false, so we exit the loop.
-
Print the Final Values
After exiting the loop, we use
printf
to output the final values of $a$ and $b$:
- The final values are $a = 3$ and $b = 2$.
- Final Output Thus, the output will be: $$ printf("%d %d", a, b); \implies printf("%d %d", 3, 2); $$
The final output will be 3 2
.
More Information
In this code, the loop modifies both variables based on the condition. The loop behaves differently than expected because the value of b
is set to 2
, which is less than a
once incremented.
Tips
There's a potential confusion between the values of a
and b
as they are updated. A common mistake is to not track how the values change in each iteration of the loop or to assume the loop runs more than once without reevaluating the updated condition.
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