The graph of a linear equation passes through the points (-4, 1) and (4, 6). Select all the points that are also solutions to this equation.
Understand the Problem
The question asks us to find all points that are also solutions to the linear equation defined by the two points given: (-4, 1) and (4, 6). The goal is to determine which of the provided points lie on the same line represented by this equation.
Answer
The points that are also solutions to the equation are $(0, 3.5)$ and $(12, 11)$.
Answer for screen readers
The points that are also solutions to the equation are $(0, 3.5)$ and $(12, 11)$.
Steps to Solve
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Calculate the Slope of the Line To find the slope $m$ of the line passing through the points $(-4, 1)$ and $(4, 6)$, use the formula: $$ m = \frac{y_2 - y_1}{x_2 - x_1} $$ Here, $(x_1, y_1) = (-4, 1)$ and $(x_2, y_2) = (4, 6)$. $$ m = \frac{6 - 1}{4 - (-4)} = \frac{5}{8} $$
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Find the Equation of the Line Using the slope-intercept form $y = mx + b$, we can find the y-intercept $b$ using one of the points. Let's use $(-4, 1)$: $$ 1 = \left(\frac{5}{8}\right)(-4) + b $$ Solving for $b$: $$ 1 = -\frac{20}{8} + b $$ $$ b = 1 + \frac{20}{8} = 1 + 2.5 = 3.5 $$ Thus, the equation of the line is: $$ y = \frac{5}{8}x + 3.5 $$
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Check Each Given Point We will now substitute each given point into the equation to see if it satisfies it.
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For $(0, 3.5)$: $$ 3.5 = \frac{5}{8}(0) + 3.5 \quad \text{(True)} $$
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For $(8, 5)$: $$ 5 = \frac{5}{8}(8) + 3.5 $$ $$ 5 = 5 + 3.5 \quad \text{(False)} $$
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For $(12, 11)$: $$ 11 = \frac{5}{8}(12) + 3.5 $$ $$ 11 = 7.5 + 3.5 \quad \text{(True)} $$
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For $(-6, 0)$: $$ 0 = \frac{5}{8}(-6) + 3.5 $$ $$ 0 = -3.75 + 3.5 \quad \text{(False)} $$
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For $(5, 6)$: $$ 6 = \frac{5}{8}(5) + 3.5 $$ $$ 6 = 3.125 + 3.5 \quad \text{(False)} $$
- List of Valid Points The points that satisfy the equation are: $(0, 3.5)$ and $(12, 11)$.
The points that are also solutions to the equation are $(0, 3.5)$ and $(12, 11)$.
More Information
When calculating points on a line represented by a linear equation, substituting each point into the equation checks if they satisfy it. Here, we determined the relationship between $x$ and $y$ through the slope and intercept.
Tips
- Miscalculating the slope can lead to an incorrect equation of the line.
- Failing to correctly substitute the x-values into the line equation to check if the calculated y-values match can lead to wrong conclusions.
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