Find lim x→-2 h(x).

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Understand the Problem

The question is asking for the limit of the function h(x) as x approaches -2. The function is piecewise, meaning it has different expressions based on the value of x, and we need to evaluate the limit from both sides of -2 to determine the result.

Answer

The limit as $x$ approaches $-2$ is $-10$.
Answer for screen readers

The limit is $-10$.

Steps to Solve

  1. Evaluate the limit from the left side

To find the limit of $h(x)$ as $x$ approaches $-2$ from the left ($x \to -2^-$), we use the expression for $h(x)$ when $x < -2$. This is given by:

$$ h(x) = 5x $$

Now, plug in $x = -2$:

$$ h(-2) = 5(-2) = -10 $$

  1. Evaluate the limit from the right side

Next, we calculate the limit as $x$ approaches $-2$ from the right ($x \to -2^+$). We use the expression for $h(x)$ when $x \geq -2$. This is:

$$ h(x) = x^3 - 2 $$

Again, substitute $x = -2$:

$$ h(-2) = (-2)^3 - 2 = -8 - 2 = -10 $$

  1. Check if the limits are equal

Since both the limits from the left and the right are equal:

$$ \lim_{x \to -2^-} h(x) = -10 $$

$$ \lim_{x \to -2^+} h(x) = -10 $$

Thus, the overall limit exists and is given by:

$$ \lim_{x \to -2} h(x) = -10 $$

The limit is $-10$.

More Information

In the context of limits for piecewise functions, both one-sided limits must be equal for the overall limit to exist. Here, we found that both sides approached $-10$, confirming the limit.

Tips

Common mistakes include:

  • Forgetting to evaluate the one-sided limits separately.
  • Miscalculating the function values when plugging in the limits.

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