Consider the same wing operating at 100 m/s. At a point on the chord, the pressure coefficient is Cp = -0.6. Find the pressure difference (Δp) at that point.
Understand the Problem
The question is asking to calculate the pressure difference at a specific point on a wing based on the given pressure coefficient and velocity.
Answer
The pressure difference is $\Delta p = -3675 \text{ Pa}$.
Answer for screen readers
The pressure difference at that point is $\Delta p = -3675 \text{ Pa}$.
Steps to Solve
- Understanding the pressure coefficient formula
The pressure difference ($\Delta p$) can be calculated using the formula: $$ \Delta p = C_p \cdot \frac{1}{2} \rho V^2 $$ where $C_p$ is the pressure coefficient, $\rho$ is the air density, and $V$ is the velocity.
- Identify the variables
In this problem:
- Given $C_p = -0.6$
- Given $V = 100 \text{ m/s}$
Assuming the air density ($\rho$) at standard conditions is approximately $1.225 \text{ kg/m}^3$.
- Substituting values into the formula
Now, substituting the values into the equation:
$$ \Delta p = -0.6 \cdot \frac{1}{2} \cdot 1.225 \cdot (100)^2 $$
- Calculate the right side
First, calculate $ \frac{1}{2} \cdot 1.225 \cdot (100)^2 $:
$$ \frac{1}{2} \cdot 1.225 \cdot 10000 = 6125 $$
Now substitute this back to find $\Delta p$:
$$ \Delta p = -0.6 \cdot 6125 $$
- Final Calculation
Calculating the final pressure difference:
$$ \Delta p = -3675 \text{ Pa} $$
The pressure difference at that point is $\Delta p = -3675 \text{ Pa}$.
More Information
This pressure difference indicates that the pressure at the point on the wing is lower than the atmospheric pressure, which is typical for airflow over a wing and contributes to lift.
Tips
- Not using the correct value for air density. It's essential to use a standard value or the specific conditions given.
- Forgetting to multiply by $1/2$ in the formula, which is crucial.
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