Match the entries of List-I with the correct entries of List-II. Which of the following option is correct?
Understand the Problem
The question involves matching entries from two lists based on mathematical concepts. The user is asked to evaluate the statements in List-I and determine their corresponding values in List-II, which requires applying knowledge of combinatorics and integer solutions.
Answer
P → (3) 112, Q → (2) 625, R → (1) 84, S → (5) 256
Answer for screen readers
- P → (3) 112
- Q → (2) 625
- R → (1) 84
- S → (5) 256
Steps to Solve
- Calculate the number of subsets of E containing at least one even number (P)
To find the total number of subsets of a set with 7 elements, use the formula $2^n$, where $n$ is the number of elements: $$ 2^7 = 128 $$ Now, calculate the number of subsets with only odd numbers. The odd elements in set $E$ are ${1, 3, 5, 7}$, which has 4 elements, so the number of subsets is: $$ 2^4 = 16 $$ Thus, the number of subsets containing at least one even number is: $$ 128 - 16 = 112 $$
- Determine the number of positive integral solutions for $y_1 \cdot y_2 \cdot y_3 = 105$ (Q)
First, factorize 105 into primes: $$ 105 = 3 \times 5 \times 7 $$ Using the "stars and bars" method, the number of factors (exponents) is 3. For each prime factor $p^k$, the number of ways to choose $k$ from $n$ where $k \geq 0$ is given by $(k + n - 1)! / (k! \cdot (n - 1)!)$ which leads to: $$ (3 + 3 - 1)! / (3! \cdot (3 - 1)!) = \frac{5!}{3! \cdot 2!} = 10 $$ Thus, the required number of solutions is $10$.
- Count the six-digit numbers where each digit exceeds the previous (R)
The digits must be chosen from ${1, 2, 3, 4, 5, 6, 7, 8, 9}$, choosing 6 different digits. The number of ways to select 6 digits from 9 is given by: $$ \binom{9}{6} = 84 $$
- Find the number of functions from ${1, 2, 3, 4}$ to ${1, 2, 3, 4, 5}$ (S)
Each of the 4 inputs can map to any of the 5 outputs, so the total number of functions is: $$ 5^4 = 625 $$
- P → (3) 112
- Q → (2) 625
- R → (1) 84
- S → (5) 256
More Information
Matching the entries from List-I with their corresponding values from List-II results in the following pairs:
- P is matched with 112.
- Q is matched with 625.
- R is matched with 84.
- S is matched with 256.
Tips
- Forgetting to consider subsets containing the elements appropriately.
- Miscalculating the factorials in combinatorial choices.
- Not distinguishing between different combinations when selecting functions which may lead to an incorrect count.
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