A drinking water sample contains mass concentration in mg/L? Assume 1 kg (1000 g) solution. 1 = x / (1000 * a) × 10^6

Question image

Understand the Problem

The question is asking how to calculate the mass concentration of a drinking water sample in mg/L, using the provided formula which relates mass and concentration.

Answer

$$ x = \frac{1000 \cdot a}{10^6} $$
Answer for screen readers

The mass concentration of the drinking water sample is given by the formula:

$$ x = \frac{1000 \cdot a}{10^6} $$

This means that if $a$ is known, you can directly calculate the concentration in mg/L.

Steps to Solve

  1. Understanding the Equation

    Given the equation:

    $$ 1 = \frac{x}{1000 \cdot a} \times 10^6 $$

    This equation relates the concentration ($x$) to $a$, where $a$ is the factor you need to determine for your specific solution.

  2. Rearranging the Equation

    To isolate $x$, you can first rearrange the equation:

    $$ x = 1 \cdot (1000 \cdot a) \div 10^6 $$

    Simplifying this gives us:

    $$ x = \frac{1000 \cdot a}{10^6} $$

  3. Simplifying the Expression

    Now, you can simplify further:

    $$ x = \frac{1000}{10^6} \cdot a $$

    This simplifies to:

    $$ x = \frac{1}{1000} \cdot a $$

  4. Calculating Mass Concentration

    Suppose you have a specific value for $a$. You can substitute it into this simplified equation to find the mass concentration in mg/L:

    $$ \text{Concentration in mg/L} = \frac{a}{1000} $$

  5. Finalizing the Calculation

    For example, if $a$ were to be given as 300, you would substitute it into the equation:

    $$ x = \frac{300}{1000} = 0.3 \text{ mg/L} $$

The mass concentration of the drinking water sample is given by the formula:

$$ x = \frac{1000 \cdot a}{10^6} $$

This means that if $a$ is known, you can directly calculate the concentration in mg/L.

More Information

Mass concentration in dilute solutions is usually measured in mg/L, which helps in assessing the quality of water.

Tips

  • Forgetting to convert the units when dealing with mass and volume.
  • Not correctly rearranging the equation to isolate the variable of interest ($x$).
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