(a) Determine the relativistic momentum of the object. (b) Determine the total relativistic energy, in joules, of the object according to a stationary observer.

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Understand the Problem

The question is asking to calculate two things related to an object with a given rest mass and speed: (a) the relativistic momentum and (b) the total relativistic energy as seen by a stationary observer. This involves using the principles of relativity.

Answer

(a) The relativistic momentum is approximately $4.14 \times 10^8 \, kg \cdot m/s$; (b) The total relativistic energy is approximately $2.54 \times 10^{17} \, J$.
Answer for screen readers

(a) The relativistic momentum of the object is approximately $4.14 \times 10^8 , kg \cdot m/s$.

(b) The total relativistic energy of the object is approximately $2.54 \times 10^{17} , J$.

Steps to Solve

  1. Calculate the Lorentz Factor ($\gamma$)

The Lorentz factor is given by the formula:

$$ \gamma = \frac{1}{\sqrt{1 - \left( \frac{v}{c} \right)^2}} $$

Here, $v = 0.81c$. Substituting this in:

$$ \gamma = \frac{1}{\sqrt{1 - (0.81)^2}} = \frac{1}{\sqrt{1 - 0.6561}} = \frac{1}{\sqrt{0.3439}} \approx 1.708 $$

  1. Calculate the Relativistic Momentum ($p$)

The formula for relativistic momentum is:

$$ p = \gamma m v $$

Substituting the known values ($m = 1.2 , \text{kg}$, $v = 0.81c$, and $\gamma \approx 1.708$):

$$ p = (1.708)(1.2)(0.81c) \approx 1.688 , kg \cdot m/s \enspace \text{(after substituting $c \approx 3 \times 10^8 , m/s$)} $$

Calculating $p$:

$$ p \approx (1.708)(1.2)(0.81) \times 3 \times 10^8 \approx 41.4 \times 10^7 , kg \cdot m/s \approx 4.14 \times 10^8 , kg \cdot m/s $$

  1. Calculate Total Relativistic Energy ($E$)

The total relativistic energy can be calculated using the formula:

$$ E = \gamma mc^2 $$

Substituting in the values:

$$ E = (1.708)(1.2)(c^2) = (1.708)(1.2)( (3 \times 10^8)^2 ) $$

Calculating further:

$$ E = (1.708)(1.2)(9 \times 10^{16}) \approx 2.54 \times 10^{17} , J $$

(a) The relativistic momentum of the object is approximately $4.14 \times 10^8 , kg \cdot m/s$.

(b) The total relativistic energy of the object is approximately $2.54 \times 10^{17} , J$.

More Information

The calculations are based on Einstein's theory of relativity, which is essential for understanding high-speed objects. The Lorentz factor accounts for the effects of speed on time and momentum.

Tips

  • Forgetting to convert the speed term when applying in momentum or energy equations.
  • Mistaking the formula for classical momentum-energy for its relativistic versions.
  • Incorrect calculations with the Lorentz factor which can significantly impact the outcomes.

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