Arjuna JEE (2024) Work, Power & Energy PDF
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Uploaded by ImmenseAmethyst
2024
Arjuna JEE
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Summary
These are practice problems for the Arjuna JEE 2024 exam covering Work, Power, and Energy. The problems involve applying concepts related to force, displacement, and energy to determine work.
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1 Arjuna JEE (2024) Work, Power & Energy DPP-...
1 Arjuna JEE (2024) Work, Power & Energy DPP-01 1. A force F = ( 2iˆ + 3 ˆj + 2kˆ ) N acts on a particle of 4. Adjacent figure shows the force displacement graph of a moving body, the work done in displacement mass m. The particle starts from points A (1, 2,1) body from x = 0 to x = 35 m is equal to and moves to point B (3, 4, 3). What is the total work done by the force on the particle? (1) 14 J (2) 12 J (3) 16 J (4) 10 J 2. Find the work done by the force by the force till 4 m (1) 50 J (2) 25 J in the given graph. (3) 287.5 J (4) 200 J 5. The relationship between force and position is shown in the figure given (in one dimensional case). The work done by the force in displacing a body from x = 1 cm to x = 5 cm is (1) 30 J (2) 15 J (3) 10 J (1) 20 ergs (2) 60 ergs (4) 20 J (3) 70 ergs (4) 700 ergs 3. A force, F = 2iˆ + 3 ˆj, acts on a particle. The particle 6. A body of mass 6 kg is under a force which causes starts from point O (0, 0) and moves to point t2 A (2, 4). Find the total work done by force F on the displacement in it given by S = metres which t is 4 particle. time. The work done by the force in 2 seconds is (1) 12 J (2) 9 J (3) 6 J (4) 3 J 7. A body contained to move in y-direction is subjected ( ) to a force given by F = −2iˆ + 15 ˆj + 6kˆ N. The (1) 16 J work done by this force in moving the body a distance of 10 m along the y-axis is (2) 12 J (1) 20 J (2) 150 J (3) 10 J (3) 160 J (4) 190 J (4) 0J 2 8. ( ) A force F = 5iˆ + 3 ˆj newton is applied over a 10. A force F acting on an object varies with distance x as shown in the figure. particle which displaces it from its origin to the ( ) point r = 2iˆ –1 ˆj metres. The work done on the particle is (1) –7 joules (2) +13 joules (3) +7 joules (4) +11 joules 9. ( ) Due to the force F = 4iˆ + 4 ˆj N a body shifted The work done by the force in moving the object from origin to the point (5 m, 6 m). The work done from x = 0 to x = 8 m is by the force is (1) 10 J (2) 80 J (1) 44 J (3) – 40 J (4) 40 J (2) 22 J (3) 4 J 11. A 2 kg mass lying on a table is displaced in the (4) Zero horizontal direction through 50 cm. The work done by the normal reaction will be - (1) 0 (2) 100 joule (3) 100 erg (4) 10 joule 3 Note: Kindly find the Video Solution of DPPs Questions in the DPPs Section. Answer Key 1. (1) 7. (2) 2. (1) 8. (3) 3. (1) 9. (1) 4. (3) 10. (1) 5. (1) 11. (1) 6. (4) PW Web/App - https://smart.link/7wwosivoicgd4 Library- https://smart.link/sdfez8ejd80if