Variation Form 4 PDF
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Uploaded by WellManagedOphicleide
Vieux Fort Comprehensive Secondary School
Ms Octave
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Summary
This document is a set of practice questions on variation, covering direct and inverse variation. The examples illustrate how to find the constant of proportionality and solve problems related to these concepts. The questions are aimed at Form 4 level.
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VARIATION Ms Octave Form 4 Variation Variation is where one variable is proportional to another variable by a constant proportion 𝑘. The symbol for Variation is ∝ Types of Variation: 1. Direct Variation 2. Indirect / Inverse Variation ...
VARIATION Ms Octave Form 4 Variation Variation is where one variable is proportional to another variable by a constant proportion 𝑘. The symbol for Variation is ∝ Types of Variation: 1. Direct Variation 2. Indirect / Inverse Variation Direct Variation 𝑦 is directly proportional to 𝑥. If 𝑦 = 10 and 𝑥 = 2.5 Determine the value of: a. The constant proportion 𝑘. b. The value of 𝑥 when 𝑦 = 20 c. The value of 𝑦 when 𝑥 = 1.25 Direct Variation 1. Write the statement using the mathematical symbol for proportional 𝑦 is directly proportional to 𝑥. 𝒚 ∝ 𝒙. 2. Express statement above as an equation ; factoring the constant proportion 𝑘. The constant proportion 𝑘 is multiplied to the second variable. 𝒚 = 𝒌 × 𝒙. Direct Variation 3. Determine the value of 𝑘, by using the value given at the beginning of the question for each variable that is 𝑦 = 10 and 𝑥 = 2.5. Every question will entail a value for each variable, so that the constant proportion 𝑘 is calculated. 𝒚=𝒌× 𝒙 𝟏𝟎 = 𝒌 × 𝟐. 𝟓 𝟏𝟎 =𝒌 𝟐. 𝟓 (a) The constant proportion is 𝒌 = 𝟒. Direct Variation 4. Use the value of 𝑘 to substitute into the original formula 𝒚 = 𝒌 × 𝒙 to determine the value of 𝑥 𝑎𝑛𝑑 𝑦 𝑖𝑛 𝑏 𝑎𝑛𝑑 𝑐 𝑏𝑒𝑙𝑜𝑤. New equation: 𝒚 = 𝟒 𝒙 (b) The value of 𝑥 when 𝑦 = 20 𝒚=𝟒𝒙 𝟐𝟎 = 𝟒 × 𝒙 𝒙 = 𝟐𝟎/𝟒 𝒙=𝟓 Direct Variation (c) The value of 𝑦 when 𝑥 = 1.25 𝒚=𝟒𝒙 𝒚 = 𝟒 × 𝟏. 𝟐𝟓 𝒚=𝟓 Indirect/Inverse Variation A is varies inversely as the square of R. If A = 3 and R = 2 Determine the value of: a. The constant proportion 𝑘. b. The value of A when R = 4 c. The value of R when A = 12 Indirect/Inverse Variation 𝟏 𝑨∝ 𝑹² 𝟏 𝑨=𝒌× 𝑹² 𝒌 𝑨= 𝑹² Indirect/Inverse Variation (a) Determining the value of 𝑘. If A = 3 and R = 2 𝒌 𝟑= 𝟐² 𝒌 𝟑= 𝟒 𝒌=𝟑×𝟒 𝒌 = 𝟏𝟐 Indirect/Inverse Variation 𝒌 𝑨= 𝑹² 𝒌 = 𝟏𝟐 𝟏𝟐 New equation is : 𝑨 = 𝑹² (b) The value of A when R = 4 𝟏𝟐 𝑨= 𝟒² 𝟏𝟐 𝑨= 𝟏𝟔 𝑨 = 𝟎. 𝟕𝟓 Indirect/Inverse Variation (c) The value of R when A = 12 𝟏𝟐 𝑨= 𝑹² 𝟏𝟐 𝟏𝟐 = 𝑹² 𝟏𝟐 𝑹² = 𝟏𝟐 𝑹² = 𝟏 𝑹= 𝟏 𝑹=𝟏