Practice Exam 2 ODD PAGES ONLY PDF

Loading...
Loading...
Loading...
Loading...
Loading...
Loading...
Loading...

Summary

This document is a practice exam containing multiple-choice questions (MCQs) related to biology. The questions cover topics such as genetics, evolution, and population dynamics. It appears to be focused on high school or undergraduate level of study.

Full Transcript

4. A patient with malaria is given the dilig chloroquinc to treat the parasitic infection. However the Plastnodiutn population has a 30% frequency of a dominant allele for chloroquine-resistance. What percent of the Plasmodium population will be killed by the treatment? A. 100% 49%...

4. A patient with malaria is given the dilig chloroquinc to treat the parasitic infection. However the Plastnodiutn population has a 30% frequency of a dominant allele for chloroquine-resistance. What percent of the Plasmodium population will be killed by the treatment? A. 100% 49% 64% D. 70% E. 90% 5. If the DNA sequence coding for the amino acid valine is GTA, what is the tRNA anticodon for valine? A. CAT B. ATG c. GAU D. GUA E. None of the above 6. In cats, white spotting of the fur is dominant to no white spots, and the white spotting has a penetrance of 40%. If two heterozygous cats have a kitten, what is the probability they will have white spots? A. 0.25 B. 0.3 C. 0.4 D. 0.75 E. None of the above 7. Which of the below scenarios are correctly matched with the likely mode of inheritance? A. A black chicken and a grey chicken reproduce resulting in offspring with both grey and black feathers = codominance B. A white chicken and a dark brown chicken reproduce resulting in light brown chicken offspring = incomplete dominance C. Tail feather length is a recessive trait controlled by one gene. In a flock of chickens, 10 have the genotype aa which results in long tail feathers, however only 5 chickens express the long tail feathers trait = epistasis. D. More than one of the above. E. All of the above 3 11. The presence of nose warts is determined by two alleles at a single locus. The observed phenotypes in a random sample of witch and warlock noses were very warty (WW), few warts (W w), and no warts (ww). Genetic analysis of witches and warlocks revealed that allelic frequencies were W=0.60 and w=0.40. After their frolicking on Halloween, the genotypic frequencies of the witch and warlock offspring in the next generation were: WW = 0.64, ww = 0.32 and ww = 0.04. This finding supports which of the following conclusions? A. Very warty witches and warlocks appear to be at a selective advantage within this population. B. The observed genotypic frequencies agree with Hardy-Weinberg expectations. C. The frequency of witch and warlock offspring with few warts (Ww) are evidence of a heterozygote advantage. D. Mates with no nose warts are preferred by both witches and warlocks in this population. E. Disruptive selection altered expected genotype frequencies. 12. Some werewolves exhibit a recessive condition first discovered in Transylvania, in which homozygous recessive werewolves are bald. The frequency of these bald werewolves in the population is 0.09. Assuming Hardy-Weinberg equilibrium, what is the frequency of hairy werewolves in the population? A. 0.7 B. 0.9919 c. D. 0.49 E. 0.91 13. Darwin and Wallace observed that: A. Under field conditions, the size of a population changes significantly over long periods of time. B. Sexual reproduction appears to be the principle cause of natural selection. C. There is considerable variation among members of a single species and variations are largely heritable. D. More than one of the above. E. All of the above. 5 17. eventually Two species of fish shared a common ancestor in a river system. The river was split into two sections by a dam, separating the two fish populations for many generations. Years later, the dam is removed and the two fish populations (now considered two species) are again sympatric and found in the same section of the river. However, Species 1 primarily lives close to the river's shore in shallow water, and Species 2 lives in deeper areas in the middle of the river, but there is a small amount of overlap in their habitats. Scientists collect both fish species to study and they observe both species can hybridize, but the hybrid offspring do not survive to reproductive age. What is true of these two fish species? A. This is an example of prezygotic isolation of gene pools via seasonal isolation. B. This is an example of postzygotic isolation of gene pools. C. Over time, these two fish species are likely to merge back into one species. D. These species underwent sympatric speciation and then secondary contact. E. More than one of the above are true. 18. In a population of 800 feral cats, the allele for yellow eyes is dominant to the allele for orange eyes. Within the population, there are 600 individuals with yellow eyes and the rest with orange eyes. What would be the predicted frequency of heterozygotes? A. 0.50 B. 0.38 c. 0.24 D. 0.75 E. There is not enough information to solve the problem. 19. There is a large population of >5,000 spotted salamanders in a local wetland. Researchers are attempting to re-populate another local pond with spotted salamanders. All the salamanders in this pond were killed due to a severe winter freeze the previous year. Researchers plan to take 20 salamanders from the large wetland population to transplant to the pond with hopes the pond will eventually increase to a population size of about 200 salamanders. Which of the following will be true of the salamander populations? A. The creation by the researchers of the pond salamander population is an example of a founder effect. B. The wetland and pond salamander populations will have the same amount of genetic diversity. C. The wetland salamander population is likely to be susceptible to genetic drift. D. Mutations in the pond population would increase genetic diversity, but mutations in the wetland population would decrease genetic diversity. E. More than one of the above are true. 7 23. A child has sex-linked red-green color blindness, but both parents have normal vision. From this information it can be inferred that: A. The child is male. B. The child's maternal grandparents carried this trait. C. The child's paternal grandfather was also color blind. D. More than one of the above. E. All of the above. A woman with type A blood has one child with type AB blood. She finds out she is pregnant again, but after she gives birth, the father of her first child claims that he is not the father of the second child. The second child has type O blood. If the man fathered the first child, but LQ_! the second, what blood type(s) must he be? A. B, AB B. C. only AB D. only A E. None of the above 25. Which of the following is an example of a prezygotic barrier to reproduction? A. Two species of birds use different mating calls to attract a mate. B. Two closely related plant species occur in the same meadow. Due to differences in flower structure, one plant species is only able to be pollinated by bees, and the second species is only pollinated by butterflies. C. When a horse and a donkey are bred, they produce a mule, which is unable to reproduce. D. Two of the above E. All of the above 9 28. You work as a fisheries scientist and are tasked with trying to control the invasive sea lamprey in an important river watershed. To kill sea lamprey, you treat a section of a river with the chemical TFM, which is a lampricide (a chemical to Ell lamprey). Before spraying, the frequency of the recessive allele in the population that makes sea lamprey resistant to TFM is 10%. After spraying the recessive allele frequency is 80%. What is true of the lamprey population? A. Before spraying, the frequency of resistant lamprey is 1% B. Before spraying, the frequency of susceptible (i.e., not resistant) lamprey is 81% C. After spraying, the frequency of susceptible (i.e., not resistant) lamprey is 36% D. More than one of the above are true. E. All of the above are true. 29. If thymine makes up 15% of the bases of a double stranded DNA sample, which of the following statements is incorrect? A. 15% would be uracil B. 35%would be cytosine C. 50% would be pyrimidines D. Two of the above are incorrect E. All of the above are incorrect 30. Marshmallow the cat is homozygous for a gene that makes the end of her tail curl. The recessive allele at this locus results in a curly tail, and the dominant allele results in a straight tail. If Marshmallow has 3 kittens in 3 different litters (= independent events) with Burt, the straight-tailed, heterozygous male cat, what is the probability that I of the 3 kittens will be curly tailed? A. 0.125 B. 0.375 c. 0.500 D. 0.750 E. 1.000 11

Use Quizgecko on...
Browser
Browser