Winter Examination 2022-23 - BTEIC_302 & NETWORK THEORY PDF

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2022

DR. BABASAHEB AMBEDKAR TECHNOLOGICAL UNIVERSITY, LONERE

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network theory electrical engineering network analysis electronics engineering

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This is a past paper from DR. BABASAHEB AMBEDKAR TECHNOLOGICAL UNIVERSITY, LONERE for the Winter 2022-2023 academic year. The paper covers Network Theory, a subject in electrical and electronics engineering. It includes different types of network analysis questions.

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DR. BABASAHEB AMBEDKAR TECHNOLOGICAL UNIVERSITY, LONERE Winter Examination – 2022-23 Course: B. Tech. Branch: E&I Semester :3 Subject Code & Name: BTEIC_302 & NETWORK THEORY Max Marks: 60 Date:11.03.23...

DR. BABASAHEB AMBEDKAR TECHNOLOGICAL UNIVERSITY, LONERE Winter Examination – 2022-23 Course: B. Tech. Branch: E&I Semester :3 Subject Code & Name: BTEIC_302 & NETWORK THEORY Max Marks: 60 Date:11.03.23 Duration: 3 Hr. Instructions to the Students: 1. All the questions are compulsory. 2. The level of question/expected answer as per OBE or the Course Outcome (CO) on which the question is based is mentioned in ( ) in front of the question. 3. Use of non-programmable scientific calculators is allowed. 4. Assume suitable data wherever necessary and mention it clearly. (Level/CO) Marks Q. 1 Solve Any Two of the following. 12 A) Define (i)Non-Linear Network (ii)Passive Network (iii)Distributed 6 Network B) Explain classification of energy sources 6 C) Explain in detail Node analysis with an example 6 Q.2 Solve Any Two of the following. 12 A) Explain maximum power transfer theorem with an example 6 B) Discuss in detail obtaining delta network impedances from star network 6 impedances C) State & Prove Superposition theorem 6 Q. 3 Solve Any Two of the following. 12 A) List out properties of Laplace transform 6 B) What is the transient & steady state response for RC circuit for the 6 following inputs (i) Unit Ramp (ii)Unit Impulse C) Write a note on significance of general & particular solutions 6 Q.4 Solve Any Two of the following. 12 A) Explain condition of Symmetry in Y parameters 6 B) Explain Z parameters in detail 6 C) Obtain Laplace transform of (i)Unit Step (ii) Unit Ramp signals 6 Q. 5 Solve Any Two of the following. 12 A) What is Parallel resonance? Explain in detail 6 B) Explain the parameters related to filter (i)Frequency response (iii)Cut 6 off frequency (iii)Pass Band C) Explain Low Pass Filter in detail 6 *** End *** 05 767 5C0 E7 490 1D 5FC 0A 50F 6FAAA7 76 5 E 49 1 5F 0 50 6 7 76 75C C0E 749 01DD5F C0AA50 F6F FAAA770 086 7 75 0E 4 01 5F C0 5 F6 A 77 86 05 67 C0 7 90 D5 C A 0F FA A7 08 0 76 5C E 49 1D F 0 50 6 A 7 6 57 75 5C 0E7 749 01D 5F C0AA50 F6F FAA 770 0860 057 675 C0E 0 C F 6 C C0 0E74 490 1D5 5FC 0A 50F 6FAAA7 7708 8605 576 75C 0E 749 E7 90 1D FC 0A 50F 6F A 70 60 76 75C 0E 749 01D 0E 49 1D 5F 0 50 6F AA 77 86 57 75 0 74 01 5 74 0 5 C A5 F A 7 08 05 6 C E7 9 D F 74 901 1D5 FC0 0A5 0F6 6FA A77 708 605 767 75C0 0E7 490 01D 5FC C0A 9 F 0 A 6 7 4 5 5 49 01DD5F C0AA50 F6F FAA 770 086 057 675 5C0E E74 901 1D5 FC0 0A5 0F6 01 5F C0 5 F6 A 77 86 05 67 C0 7 90 D5 FC A 0F FA 90 D5 C A 0F FA A7 08 0 76 5C E 49 1D F 0A 50 6F A 1D F 0 50 6 A 7 6 57 75 0 74 01 5 C 5 F A 7 1D 5FC C0AA50 F6F FAA 770 0860 057 675 C0E E74 901 D5F FC0 0A5 0F6 6FA A77 7086 sources. 5F 0A 50 F6F AA 77 86 57 675 C0 74 901 D5 C0 A5 0F6 FA A7 08 05 C0 5 F6 A 77 08 05 67 C0 E7 90 D FC A 0F FA A7 70 60 76 an example. A5 0F6 FA A7 08 605 767 5C E7 490 1D 5FC 0A 50F 6F A 70 860 576 75 0F FA A7 708 60 76 5C 0E 49 1D 5F 0A 50 6F AA 770 86 57 75 C0E 6F A 70 60 576 75 0E 74 01 5F C0 5 F6 A 77 86 05 67 C0 7 AA 77 86 57 75 C0 74 901 D5 C A5 0F FA A7 08 05 767 5C E7 490 Max Marks: 60 77 086 057 675 C0 E74 901 D5 FC 0A5 0F6 6FA A7 708 605 767 5C 0E7 490 1D 08 05 67 C E7 90 D FC 0A 0F F A 70 60 76 5C 0E 49 1D 5F 60 76 5C 0E 49 1D 5F 0A 50 6F AA 77 86 57 75 0 74 01 5 C0 57 75 0E 74 01 5 C0 5 F6 A 77 08 05 67 C E7 90 D FC A 67 C0 7 90 D5 FC A 0F FA A7 08 60 76 5C 0E 49 1D 5F 0A 50 5C E7 49 1D F 0A 50 6F A 70 60 57 75 0E 74 01 5 C0 5 F6 0E 49 01D 5F C0 50 F6F AA 77 86 57 675 C0 74 901 D5 FC A5 0F FA 74 01 5 C0 A5 F6 A 77 08 05 67 C0 E7 90 D FC 0A 0F 6FA A7 90 D5 FC A 0F FA A7 08 60 76 5C E 49 1D 5F 0A 50 6F A 70 1D FC 0A 50 6F A 70 60 57 75 0E 74 01 5F C0 5 F6 A 77 86 Instructions to the Students: 5F 0A 50 F6F AA 77 86 57 675 C0 74 901 D5 C0 A5 0F6 FA A7 08 05 C0 5 F6 A 77 08 05 67 C0 E7 90 D FC A 0F FA A7 70 60 76 A5 0F6 FA A7 08 605 767 5C E7 490 1D 5FC 0A 50F 6F A 70 860 576 75 Q.2 Solve Any Two of the following. Q. 1 Solve Any Two of the following. Q. 3 Solve Any Two of the following. 0F FA A7 708 60 76 5C 0E 49 1D 5F 0A 50 6F AA 770 86 57 75 C0E 1. Linear and non linear elements 6F A 70 60 576 75 0E 74 01 5F C0 5 F6 A 77 86 05 67 C0 7 2. Unilateral and bilateral elements AA 77 86 57 75 C0 74 901 D5 C A5 0F FA A7 08 05 767 5C E7 490 77 086 057 675 C0 E74 901 D5 FC 0A5 0F6 6FA A7 708 605 767 5C 0E7 490 1D 08 05 67 C E7 90 D FC 0A 0F F A 70 60 76 5C 0E 49 1D 5F 1. All the questions are compulsory. 60 76 5C 0E 49 1D 5F 0A 50 6F AA 77 86 57 75 0 74 01 5 C0 suitable tree and obtain the tie-set matrix. 57 75 0E 74 01 5 C0 5 F6 A 77 08 05 67 C E7 90 D FC A 67 C0 7 90 D5 FC A 0F FA A7 08 60 76 5C 0E 49 1D 5F 0A 50 Thevenin’s theorem. Refer following figure. 5C E7 49 1D F 0A 50 6F A 70 60 57 75 0E 74 01 5 C0 5 F6 0E 49 01D 5F C0 50 F6F AA 77 86 57 675 C0 74 901 D5 FC A5 0F FA A) State and Explain KVL and KCL with example 74 01 5 C0 A5 F6 A 77 08 05 67 C0 E7 90 D FC 0A 0F 6FA A7 90 D5 FC A 0F FA A7 08 60 76 5C E 49 1D 5F 0A 50 6F A 70 1D FC 0A 50 6F A 70 60 57 75 0E 74 01 5F C0 5 F6 A 77 86 B) Explain the following terms with suitable example 5F 0A 50 F6F AA 77 86 57 675 C0 74 901 D5 C0 A5 0F6 FA A7 08 05 C0 5 F6 A 77 08 05 67 C0 E7 90 D FC A 0F FA A7 70 60 76 A5 0F6 FA A7 08 605 767 5C E7 490 1D 5FC 0A 50F 6F A 70 860 576 75 0F FA A7 708 60 76 5C 0E 49 1D 5F 0A 50 6F AA 770 86 57 75 C0E Date:- 12/08/2022 6F A 70 60 576 75 0E 74 01 5F C0 5 F6 A 77 86 05 67 C0 7 AA 77 86 57 75 C0 74 901 D5 C A5 0F FA A7 08 05 767 5C E7 490 77 086 057 675 C0 E74 901 D5 FC 0A5 0F6 6FA A7 708 605 767 5C 0E7 490 1D 08 05 67 C E7 90 D FC 0A 0F F A 70 60 76 5C 0E 49 1D 5F 60 76 5C 0E 49 1D 5F 0A 50 6F AA 77 86 57 75 0 74 01 5 C0 86057675C0E74901D5FC0A50F6FAA770 57 75 0E 74 01 5 C0 5 F6 A 77 08 05 67 C E7 90 D FC A 67 C0 7 90 D5 FC A 0F FA A7 08 60 76 5C 0E 49 1D 5F 0A 50 5C E7 49 1D F 0A 50 6F A 70 60 57 75 0E 74 01 5 C0 5 F6 3. Use of non-programmable scientific calculators is allowed. 0E 49 01D 5F C0 50 F6F AA 77 86 57 675 C0 74 901 D5 FC A5 0F FA 74 01 5 C0 A5 F6 A 77 08 05 67 C0 E7 90 D FC 0A 0F 6FA A7 90 D5 FC A 0F FA A7 08 60 76 5C E 49 1D 5F 0A 50 6F A 70 1D FC 0A 50 6F A 70 60 57 75 0E 74 01 5F C0 5 F6 A 77 86 C) State the Thevenin’s theorem and find current through branch AB using B) Following figure represents a resistive network. Draw its graph. Select a 4. Assume suitable data wherever necessary and mention it clearly. 5F 0A 50 F6F AA 77 86 57 675 C0 74 901 D5 C0 A5 0F6 FA A7 08 05 C0 5 F6 A 77 08 05 67 C0 E7 90 D FC A 0F FA A7 70 60 76 Course: B. Tech Branch: Electrical Engineering and Allied Branches Subject Code & Name: BTEEC401 Network Theory Regular End Semester Examination – Summer 2022 A5 0F6 FA A7 08 605 767 5C E7 490 1D 5FC 0A 50F 6F A 70 860 576 75 A) Explain the difference between short circuit (SC) and open circuit (OC) with 0F FA A7 708 60 76 5C 0E 49 1D 5F 0A 50 6F AA 770 86 57 75 C0E which the question is based is mentioned in ( ) in front of the question. 6F A 70 60 576 75 0E 74 01 5F C0 5 F6 A 77 86 05 67 C0 7 AA 77 86 57 75 C0 74 901 D5 C A5 0F FA A7 08 05 767 5C E7 490 77 086 057 675 C0 E74 901 D5 FC 0A5 0F6 6FA A7 708 605 767 5C 0E7 490 1D 08 05 67 C E7 90 D FC 0A 0F F A 70 60 76 5C 0E 49 1D sion 60 76 5C 0E 49 1D 5F 0A 50 6F AA 77 86 57 75 0 74 01 5 57 75 0E 74 01 5 C0 5 F6 A 77 08 05 67 C E7 90 D F Sion / 67 C0 7 90 D5 FC A 0F FA A7 08 60 76 5C 0E 49 1D 5F 5C E7 49 1D F 0A 50 6F A 70 60 57 75 0E 74 01 5 C Analysis 0E 49 01D 5F C0 50 F6F AA 77 86 57 675 C0 74 901 D5 FC 74 01 5 C0 A5 F6 A 77 08 05 67 C0 E7 90 D FC 0 Evaluation DR. BABASAHEB AMBEDKAR TECHNOLOGICAL UNIVERSITY, LONERE 2. The level of question/expected answer as per OBE or the Course Outcome (CO) on Comprehen Comprehen Understand Understand Knowledge 90 D5 FC A 0F FA A7 08 60 76 5C E 49 1D 5F 0A Sem: IV C) Explain two types of energy source. Distinguish between ideal and non-ideal Understand/ Duration:- 3.45 Hr. 1D FC 0A 50 6F A 70 60 57 75 0E 74 01 5F C0 (Level/CO) 5F 0A 50 F6F AA 77 86 57 675 C0 74 901 D5 C0 A5 C0 5 F6 A 77 08 05 67 C0 E7 90 D FC A 0 A5 0F6 FA A7 08 605 767 5C E7 490 1D 5FC 0A 50F 0F FA A7 708 60 76 5C 0E 49 1D 5F 0A 50 6F A 70 60 576 75 0E 74 01 5F C0 5 F6 AA 77 86 57 75 C0 74 901 D5 C A5 0F 6 6 6 6 6 6 77 086 057 675 C0 E74 901 D5 FC 0A5 0F6 6F Marks 08 05 67 C E7 90 D FC 0A 0F F 60 76 5C 0E 49 1D 5F 0A 50 6F A 57 75 0E 74 01 5 C0 5 F6 A 67 C0 7 90 D5 FC A 0F FA A7 5 E 4 1 0 5 6 05 767 5C0 E7 490 1D 5FC 0A 50F 6FAAA7 76 5 E 49 1 5F 0 50 6 7 76 75C C0E 749 01DD5F C0AA50 F6F FAAA770 086 7 75 0E 4 01 5F C0 5 F6 A 77 86 05 67 C0 7 90 D5 C A 0F FA A7 08 0 76 5C E 49 1D F 0 50 6 A 7 6 57 75 5C 0E7 749 01D 5F C0AA50 F6F FAA 770 0860 057 675 C0E 0 C F 6 C C0 0E74 490 1D5 5FC 0A 50F 6FAAA7 7708 8605 576 75C 0E 749 E7 90 1D FC 0A 50F 6F A 70 60 76 75C 0E 749 01D 0E 49 1D 5F 0 50 6F AA 77 86 57 75 0 74 01 5 74 0 5 C A5 F A 7 08 05 6 C E7 9 D F 74 901 1D5 FC0 0A5 0F6 6FA A77 708 605 767 75C0 0E7 490 01D 5FC C0A 9 F 0 A 6 7 4 5 5 49 01DD5F C0AA50 F6F FAA 770 086 057 675 5C0E E74 901 1D5 FC0 0A5 0F6 01 5F C0 5 F6 A 77 86 05 67 C0 7 90 D5 FC A 0F FA 90 D5 C A 0F FA A7 08 0 76 5C E 49 1D F 0A 50 6F A 1D F 0 50 6 A 7 6 57 75 0 74 01 5 C 5 F A 7 1D 5FC C0AA50 F6F FAA 770 0860 057 675 C0E E74 901 D5F FC0 0A5 0F6 6FA A77 7086 5F 0A 50 F6F AA 77 86 57 675 C0 74 901 D5 C0 A5 0F6 FA A7 08 05 C0 5 F6 A 77 08 05 67 C0 E7 90 D FC A 0F FA A7 70 60 76 A5 0F6 FA A7 08 605 767 5C E7 490 1D 5FC 0A 50F 6F A 70 860 576 75 0F FA A7 708 60 76 5C 0E 49 1D 5F 0A 50 6F AA 770 86 57 75 C0E 6F A 70 60 576 75 0E 74 01 5F C0 5 F6 A 77 86 05 67 C0 7 AA 77 86 57 75 C0 74 901 D5 C A5 0F FA A7 08 05 767 5C E7 490 α will be 10 Db? 77 086 057 675 C0 E74 901 D5 FC 0A5 0F6 6FA A7 708 605 767 5C 0E7 490 1D 08 05 67 C E7 90 D FC 0A 0F F A 70 60 76 5C 0E 49 1D 5F 60 76 5C 0E 49 1D 5F 0A 50 6F AA 77 86 57 75 0 74 01 5 C0 57 75 0E 74 01 5 C0 5 F6 A 77 08 05 67 C E7 90 D FC A 67 C0 7 90 D5 FC A 0F FA A7 08 60 76 5C 0E 49 1D 5F 0A 50 5C E7 49 1D F 0A 50 6F A 70 60 57 75 0E 74 01 5 C0 5 F6 current in both the cases. 0E 49 01D 5F C0 50 F6F AA 77 86 57 675 C0 74 901 D5 FC A5 0F FA 74 01 5 C0 A5 F6 A 77 08 05 67 C0 E7 90 D FC 0A 0F 6FA A7 90 D5 FC A 0F FA A7 08 60 76 5C E 49 1D 5F 0A 50 6F A 70 1D FC 0A 50 6F A 70 60 57 75 0E 74 01 5F C0 5 F6 A 77 86 5F 0A 50 F6F AA 77 86 57 675 C0 74 901 D5 C0 A5 0F6 FA A7 08 05 C0 5 F6 A 77 08 05 67 C0 E7 90 D FC A 0F FA A7 70 60 76 (ii) Frequency at which α =10dB across inductor at any time t > 0. A5 0F6 FA A7 08 605 767 5C E7 490 1D 5FC 0A 50F 6F A 70 860 576 75 Q. 5 Solve Any Two of the following. Q.4 Solve Any Two of the following. 0F FA A7 708 60 76 5C 0E 49 1D 5F 0A 50 6F AA 770 86 57 75 C0E 6F A 70 60 576 75 0E 74 01 5F C0 5 F6 A 77 86 05 67 C0 7 AA 77 86 57 75 C0 74 901 D5 C A5 0F FA A7 08 05 767 5C E7 490 To calculate (i) L, C (filter Elements) 77 086 057 675 C0 E74 901 D5 FC 0A5 0F6 6FA A7 708 605 767 5C 0E7 490 1D 08 05 67 C E7 90 D FC 0A 0F F A 70 60 76 5C 0E 49 1D 5F B) Explain various properties of a capacitor. 60 76 5C 0E 49 1D 5F 0A 50 6F AA 77 86 57 75 0 74 01 5 C0 57 75 0E 74 01 5 C0 5 F6 A 77 08 05 67 C E7 90 D FC A 67 C0 7 90 D5 FC A 0F FA A7 08 60 76 5C 0E 49 1D 5F 0A 50 5C E7 49 1D F 0A 50 6F A 70 60 57 75 0E 74 01 5 C0 5 F6 0E 49 01D 5F C0 50 F6F AA 77 86 57 675 C0 74 901 D5 FC A5 0F FA 74 01 5 C0 A5 F6 A 77 08 05 67 C0 E7 90 D FC 0A 0F 6FA A7 90 D5 FC A 0F FA A7 08 60 76 5C E 49 1D 5F 0A 50 6F A 70 1D FC 0A 50 6F A 70 60 57 75 0E 74 01 5F C0 5 F6 A 77 86 5F 0A 50 F6F AA 77 86 57 675 C0 74 901 D5 C0 A5 0F6 FA A7 08 05 C0 5 F6 A 77 08 05 67 C0 E7 90 D FC A 0F FA A7 70 60 76 *** End *** A5 0F6 FA A7 08 605 767 5C E7 490 1D 5FC 0A 50F 6F A 70 860 576 75 A) Explain first order and second order RC and RL circuit. 0F FA A7 708 60 76 5C 0E 49 1D 5F 0A 50 6F AA 770 86 57 75 C0E 6F A 70 60 576 75 0E 74 01 5F C0 5 F6 A 77 86 05 67 C0 7 AA 77 86 57 75 C0 74 901 D5 C A5 0F FA A7 08 05 767 5C E7 490 77 086 057 675 C0 E74 901 D5 FC 0A5 0F6 6FA A7 708 605 767 5C 0E7 490 1D 08 05 67 C E7 90 D FC 0A 0F F A 70 60 76 5C 0E 49 1D 5F 60 76 5C 0E 49 1D 5F 0A 50 6F AA 77 86 57 75 0 74 01 5 C0 86057675C0E74901D5FC0A50F6FAA770 B) Explain Z-Parameters in terms of Y-parameter & h-parameters. 57 75 0E 74 01 5 C0 5 F6 A 77 08 05 67 C E7 90 D FC A A) Derive the symmetry and reciprocity condition of z-parameters. B) Derive the expression for Q factor of parallel resonating circuit. 67 C0 7 90 D5 FC A 0F FA A7 08 60 76 5C 0E 49 1D 5F 0A 50 5C E7 49 1D F 0A 50 6F A 70 60 57 75 0E 74 01 5 C0 5 F6 0E 49 01D 5F C0 50 F6F AA 77 86 57 675 C0 74 901 D5 FC A5 0F FA 74 01 5 C0 A5 F6 A 77 08 05 67 C0 E7 90 D FC 0A 0F 6FA A7 90 D5 FC A 0F FA A7 08 60 76 5C E 49 1D 5F 0A 50 6F A 70 1D FC 0A 50 6F A 70 60 57 75 0E 74 01 5F C0 5 F6 A 77 86 condition is reached. At t=0, the switch is moved to position 2. Find the t = 0. Derive the expression for the current through inductor and voltage 5F 0A 50 F6F AA 77 86 57 675 C0 74 901 D5 C0 A5 0F6 FA A7 08 05 C) An inductor with initial current I0 is connected to a resistor of R ohms at C) In following figure the switch K is kept first at position 1 and steady state C0 5 F6 A 77 08 05 67 C0 E7 90 D FC A 0F FA A7 70 60 76 A) Derive the expression for resonant frequency fr of a series resonant circuit. A5 0F6 FA A7 08 605 767 5C E7 490 1D 5FC 0A 50F 6F A 70 860 576 75 C) Design a constant K LPF with fc =1KHz and RO = 600 Ω At what frequency 0F FA A7 708 60 76 5C 0E 49 1D 5F 0A 50 6F AA 770 86 57 75 C0E 6F A 70 60 576 75 0E 74 01 5F C0 5 F6 A 77 86 05 67 C0 7 AA 77 86 57 75 C0 74 901 D5 C A5 0F FA A7 08 05 767 5C E7 490 77 086 057 675 C0 E74 901 D5 FC 0A5 0F6 6FA A7 708 605 767 5C 0E7 490 1D 08 05 67 C E7 90 D FC 0A 0F F A 70 60 76 5C 0E 49 1D 60 76 5C 0E 49 1D 5F 0A 50 6F AA 77 86 57 75 0 74 01 5 57 75 0E 74 01 5 C0 5 F6 A 77 08 05 67 C E7 90 D F 67 C0 7 90 D5 FC A 0F FA A7 08 60 76 5C 0E 49 1D 5F 5C E7 49 1D F 0A 50 6F A 70 60 57 75 0E 74 01 5 C 0E 49 01D 5F C0 50 F6F AA 77 86 57 675 C0 74 901 D5 FC Synthesis Synthesis Synthesis 74 01 5 C0 A5 F6 A 77 08 05 67 C0 E7 90 D FC 0 Evaluation Evaluation Evaluation Understand Understand Understand 90 D5 FC A 0F FA A7 08 60 76 5C E 49 1D 5F 0A 1D FC 0A 50 6F A 70 60 57 75 0E 74 01 5F C0 5F 0A 50 F6F AA 77 86 57 675 C0 74 901 D5 C0 A5 C0 5 F6 A 77 08 05 67 C0 E7 90 D FC A 0 A5 0F6 FA A7 08 605 767 5C E7 490 1D 5FC 0A 50F 0F FA A7 708 60 76 5C 0E 49 1D 5F 0A 50 6F A 70 60 576 75 0E 74 01 5F C0 5 F6 AA 77 86 57 75 C0 74 901 D5 C A5 0F 6 6 6 6 6 6 6 6 6 77 086 057 675 C0 E74 901 D5 FC 0A5 0F6 6F 08 05 67 C E7 90 D FC 0A 0F F 60 76 5C 0E 49 1D 5F 0A 50 6F A 57 75 0E 74 01 5 C0 5 F6 A 67 C0 7 90 D5 FC A 0F FA A7 5 E 4 1 0 5 6 1 2

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