Write an equation of the line in point-slope form passing through the point (-4, 1) and parallel to the given line y = -2x + 3.

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Understand the Problem

The question is asking to write the equation of a line in point-slope form that passes through a specific point and is parallel to a given line. The given line is presented in slope-intercept form, from which the slope can be extracted to use for constructing the equation of the new line.

Answer

$$ y + 1 = -2(x + 4) $$
Answer for screen readers

The equation of the line in point-slope form is:

$$ y + 1 = -2(x + 4) $$

Steps to Solve

  1. Identify the slope of the given line

The given line is in the slope-intercept form $y = -2x + 3$. Therefore, the slope $m$ is $-2$.

  1. Use the point-slope form equation

The point-slope form is given by the formula:

$$ y - y_1 = m(x - x_1) $$

where $(x_1, y_1)$ is the point through which the line passes. Here, $(x_1, y_1) = (-4, 1)$ and $m = -2$.

  1. Substitute values into the equation

Substituting the values into the point-slope form equation:

$$ y - 1 = -2(x - (-4)) $$

This simplifies to:

$$ y - 1 = -2(x + 4) $$

  1. Adjust the equation (if needed)

We can rearrange the equation:

$$ y + 1 = -2(x + 4) $$

This matches the point-slope form as requested.

The equation of the line in point-slope form is:

$$ y + 1 = -2(x + 4) $$

More Information

The point-slope form of a line is particularly useful when you know a point on the line and its slope. Because parallel lines have the same slope, we used the slope from the given line to create the new equation.

Tips

  • Forgetting to maintain the sign of the slope can lead to an incorrect equation.
  • Mixing up the coordinates when substituting values can lead to a wrong point-slope equation.

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