Which pair of numbers has an LCM of 18?
Understand the Problem
The question is asking for pairs of numbers that have a least common multiple (LCM) of 18. To find these pairs, we need to consider the factors of 18 and determine which combinations of numbers yield that LCM.
Answer
The pairs of numbers that have a least common multiple of 18 are: $(2, 9), (9, 2), (6, 18), (1, 18)$.
Answer for screen readers
The pairs of numbers that have a least common multiple of 18 are:
$(2, 9), (9, 2), (6, 18), (1, 18)$.
Steps to Solve
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List the factors of 18
The first step is to identify all the factors of 18. The factors are:
$1, 2, 3, 6, 9, 18$. -
Determine pairs of factors
Next, we need to find pairs of these factors whose greatest common divisor (GCD) is such that the LCM can be calculated directly. Recall the formula for LCM:
$$ \text{LCM}(a, b) = \frac{a \cdot b}{\text{GCD}(a, b)} $$ -
Calculate LCM for each pair
We will go through each pair of factors and calculate the LCM using our formula. We will focus on pairs $(a, b)$ where $L = 18$:-
For pairs $(2, 9)$:
- $\text{GCD}(2, 9) = 1$
- $ \text{LCM}(2, 9) = \frac{2 \cdot 9}{1} = 18 $
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For pairs $(3, 6)$:
- $\text{GCD}(3, 6) = 3$
- $ \text{LCM}(3, 6) = \frac{3 \cdot 6}{3} = 6 $ (not valid)
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For pairs $(6, 9)$:
- $\text{GCD}(6, 9) = 3$
- $ \text{LCM}(6, 9) = \frac{6 \cdot 9}{3} = 18 $
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Repeat this for pairs with $1$ and $18$:
- $(1, 18)$ gives an LCM of 18
- Other pairs do not yield 18.
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List valid pairs
After calculating, we find the valid pairs that yield an LCM of 18:
- $(2, 9)$
- $(6, 18)$
- $(1, 18)$
- $(9, 2)$ (which is the reverse of $(2, 9)$)
The pairs of numbers that have a least common multiple of 18 are:
$(2, 9), (9, 2), (6, 18), (1, 18)$.
More Information
The least common multiple (LCM) is a crucial concept in number theory used in various applications such as fractions, scheduling problems, and more.
Tips
- Not checking all possible pairs systematically, leading to missed valid combinations.
- Confusing LCM with GCD; remember that LCM deals with multiples while GCD deals with divisors.