What will be the output? int i = 5; while(--i > 0) { printf("%d ", i); if(i == 2) break; } printf("%d", i);
Understand the Problem
The question is asking for the output of a piece of C code involving a while loop that decrements a variable and prints its value until a certain condition is met. The user needs to determine which of the provided options matches the output generated by the code.
Answer
The output is `4 3 2 2`.
Answer for screen readers
The output of the code will be: 4 3 2 2
Steps to Solve
-
Initialize the variable The variable
iis initialized to 5. -
Evaluate the while loop condition The condition for the while loop is checked:
--i > 0.- First iteration:
ibecomes 4. Since 4 > 0, enter the loop. - Print 4.
- First iteration:
-
Second iteration of the loop
-
--iis evaluated again,ibecomes 3. Since 3 > 0, enter the loop. - Print 3.
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-
Third iteration of the loop
-
--iis evaluated again,ibecomes 2. Since 2 > 0, enter the loop. - Print 2.
- Check the if condition:
if(i == 2), this is true, thereforebreakis executed.
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After the loop Once out of the loop, the final value of
i(which is 2) is printed. -
Final Output Construction The printed values from the loop are "4 3 2 " and the final output is "2".
The output of the code will be: 4 3 2 2
More Information
This code uses a while loop to decrement i starting from 5, and it checks at each iteration if i is greater than 0. It prints each decremented value of i until it reaches 2, at which point it breaks out of the loop. Finally, it prints the value of i, which after breaking is still 2.
Tips
- Forgetting to account for the pre-decrement operator
--i, which changes the value ofibefore checking the condition. - Misunderstanding the behavior of the break statement, which exits the loop if the condition is met.
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