What is the molar mass of CuSO4.5H2O?

Steps to Solve

1. Identify the components in the formula

The formula for copper(II) sulfate pentahydrate is $CuSO_4 \cdot 5H_2O$. We need to identify the individual components:

• Copper (Cu)
• Sulfur (S)
• Oxygen (O)
• Hydrogen (H)

2. Find the atomic masses of each element

Using the periodic table, we can find the atomic masses for each element:

• $Cu$: 63.55 g/mol
• $S$: 32.07 g/mol
• $O$: 16.00 g/mol
• $H$: 1.01 g/mol

3. Break down the formula into its elements

From the formula $CuSO_4 \cdot 5H_2O$, we can see that:

• There is 1 Cu atom
• There is 1 S atom
• There are 4 O atoms from $SO_4$ and an additional 5 O atoms from $5H_2O$, totaling 9 O atoms
• There are 10 H atoms from $5H_2O$

4. Calculate the total mass for each element

Now, we can calculate the total mass contribution from each element:

• For Cu: $1 \times 63.55 , \text{g/mol} = 63.55 , \text{g/mol}$
• For S: $1 \times 32.07 , \text{g/mol} = 32.07 , \text{g/mol}$
• For O: $9 \times 16.00 , \text{g/mol} = 144.00 , \text{g/mol}$
• For H: $10 \times 1.01 , \text{g/mol} = 10.10 , \text{g/mol}$

5. Sum all the contributions to find the total molar mass

Finally, we sum all these contributions to find the molar mass of copper(II) sulfate pentahydrate: $$ \text{Molar Mass} = 63.55 + 32.07 + 144.00 + 10.10 = 249.72 , \text{g/mol} $$