What is the distance between point P (primates) and point C (cats) on the map?
Understand the Problem
The question is asking for the distance between two points, P and C, on a coordinate map. To find this distance, we will likely use the distance formula based on their coordinates.
Answer
The distance between points $P$ and $C$ is $2\sqrt{26}$ units.
Answer for screen readers
The distance between points $P$ and $C$ is $2\sqrt{26}$ units.
Steps to Solve
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Identify the coordinates of points P and C
By observing the graph, we note the positions of the points:
- Point $P$ (primate) is located at the coordinates $(-2, 1)$.
- Point $C$ (cat) is located at the coordinates $(8, -1)$.
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Use the distance formula
The distance $d$ between two points $(x_1, y_1)$ and $(x_2, y_2)$ is calculated using the formula: $$ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} $$
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Substitute the coordinates into the distance formula
Plugging in the coordinates of points $P$ and $C$:
- $x_1 = -2$, $y_1 = 1$
- $x_2 = 8$, $y_2 = -1$
Thus, we have: $$ d = \sqrt{(8 - (-2))^2 + (-1 - 1)^2} $$
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Calculate the differences and squares
Simplifying the expressions:
- $8 - (-2) = 8 + 2 = 10$
- $-1 - 1 = -2$
Therefore, we rewrite the equation: $$ d = \sqrt{10^2 + (-2)^2} $$
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Calculate the squares
Now we compute the squares:
- $10^2 = 100$
- $(-2)^2 = 4$
This gives us: $$ d = \sqrt{100 + 4} $$
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Find the final value of distance
Finally, calculating the root: $$ d = \sqrt{104} $$ This can further be simplified: $$ d = 2\sqrt{26} $$
The distance between points $P$ and $C$ is $2\sqrt{26}$ units.
More Information
The distance formula is a fundamental concept in coordinate geometry. It helps determine how far apart two points are on a Cartesian plane. This specific measurement, $2\sqrt{26}$, approximately equals 10.2 units when calculated numerically.
Tips
- Misidentifying coordinates: Carefully verify the coordinates of each point.
- Forgetting to square the differences: Always remember to square the differences in the distance formula.
- Not reducing radicals: Ensure to simplify the square root to its simplest form when possible.
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