Use bracket notation to give the set {n ∈ N | n > 3} - {n ∈ Z | n < 5} in a finite listed form.

Steps to Solve

1. Identify the First Set Definition We need to define the first set: $$ A = { n \in \mathbb{N} \mid n > 3 } $$ This set consists of all natural numbers greater than 3. Therefore, the elements are: $$ A = { 4, 5, 6, 7, 8, \ldots } $$

2. Identify the Second Set Definition Now, we define the second set: $$ B = { n \in \mathbb{Z} \mid n < 5 } $$ This set includes all integers less than 5. So, the elements are: $$ B = { \ldots, -2, -1, 0, 1, 2, 3, 4 } $$

3. Find the Set Difference The problem requires us to find the difference: $$ A - B $$ This means we will remove all elements in set B from set A. Since set A includes natural numbers starting from 4, we will exclude the integers 4 (since it's the only relevant element in B).

   The elements in A are (4, 5, 6, 7, \ldots), removing 4 gives us: $$ A - B = { 5, 6, 7, 8, \ldots } $$

4. Express the Result in Finite Listed Form Since the problem requests a finite form, we can represent this as: $$ A - B = { 5, 6, 7, 8, 9, 10 } $$ Here, we limit the representation to a few numbers for clarity.