The carbon chain of fatty acids is shortened by 2 carbon atoms at a time. This involves successive reactions catalysed by 4 enzymes. These act in the following order: A. Acetyl CoA... The carbon chain of fatty acids is shortened by 2 carbon atoms at a time. This involves successive reactions catalysed by 4 enzymes. These act in the following order: A. Acetyl CoA dehydrogenase, OH acyl CoA dehydrogenase, enoyl hydrase, thiolase B. Acyl CoA dehydrogenase, thiolase, enoyl hydrase, OH acyl CoA dehydrogenase C. Acyl CoA dehydrogenase, thiolose, enoyl hydrase, OH acyl CoA dehydrogenase D. Enoyl hydrase, OH acyl CoA dehydrogenase, acyl CoA dehydrogenase, acyl CoA dehydrogenase, thiolase

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Understand the Problem

The question is asking about the sequence of reactions involving specific enzymes that participate in shortening the carbon chain of fatty acids by 2 carbon atoms at a time. The provided options list different orders of enzymes involved in this process.

Answer

C. Acyl CoA dehydrogenase, thiolase, enoyl hydrase, OH acyl CoA dehydrogenase

The correct sequence is: Acyl CoA dehydrogenase, enoyl-CoA hydratase, OH acyl CoA dehydrogenase, thiolase. This corresponds to option C.

Answer for screen readers

The correct sequence is: Acyl CoA dehydrogenase, enoyl-CoA hydratase, OH acyl CoA dehydrogenase, thiolase. This corresponds to option C.

More Information

In beta-oxidation, the sequence starts with acyl CoA dehydrogenase, which introduces a double bond. Then, enoyl-CoA hydratase adds water across this bond, followed by OH acyl CoA dehydrogenase that oxidizes the hydroxyl group. Finally, thiolase cleaves the resulting molecule.

Tips

A common mistake is misidentifying the role of each enzyme and their sequence. Understanding the sequential steps in beta-oxidation helps avoid confusion.

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