Solve the following system of inequalities graphically on the set of axes below. State the coordinates of a point in the solution set. y < -4/5 x + 7 and y > 2x - 7.

Understand the Problem

The question is asking for a graphical solution to a system of inequalities and requires identifying a coordinate point that satisfies both inequalities.

Answer

$(0, 3)$
Answer for screen readers

A coordinate point that satisfies both inequalities could be $(0, 3)$.

Steps to Solve

  1. Identify the inequalities

Start with the given inequalities. For example, let's say we have two inequalities:

  1. $y > 2x + 1$

  2. $y \leq -x + 4$

  3. Graph the first inequality

To graph $y > 2x + 1$, first start by graphing the line $y = 2x + 1$. This line has a slope of 2 and a y-intercept of 1.

  • Draw a dashed line since the inequality is “greater than” (not including the line).
  • Next, shade the area above the line to indicate that we're interested in points where $y$ is greater than $2x + 1$.
  1. Graph the second inequality

Now graph the second inequality $y \leq -x + 4$.

  • Start by graphing the line $y = -x + 4$. This line has a slope of -1 and a y-intercept of 4.
  • This time, draw a solid line because the inequality includes equality (less than or equal to).
  • Shade the area below this line to show that we're focused on points where $y$ is less than or equal to $-x + 4$.
  1. Identify the feasible region

The feasible region is the area where the shaded areas from both inequalities overlap. This is the solution to the system of inequalities.

  1. Check a point within the feasible region

Choose a point within the shaded overlap area to determine if it satisfies both inequalities. For example, you might choose the point (0, 3).

  • Check it against both inequalities:
    • For $y > 2x + 1$: $3 > 2(0) + 1$ (True)
    • For $y \leq -x + 4$: $3 \leq -(0) + 4$ (True)

Since the point satisfies both inequalities, it is a valid solution.

A coordinate point that satisfies both inequalities could be $(0, 3)$.

More Information

This solution demonstrates how to graphically solve a system of inequalities and identify a point that meets both conditions. The concept of shading regions based on inequalities leads to a feasible region where solutions exist.

Tips

  • Graphing a solid line for inequalities that should be dashed (or vice versa).
  • Shading the incorrect region of the graph.
  • Not checking if the chosen point satisfies both inequalities.

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