Solve the following system of inequalities graphically on the set of axes below. State the coordinates of a point in the solution set. y < -4/5 x + 7 and y > 2x - 7.
Understand the Problem
The question is asking for a graphical solution to a system of inequalities and requires identifying a coordinate point that satisfies both inequalities.
Answer
$(0, 3)$
Answer for screen readers
A coordinate point that satisfies both inequalities could be $(0, 3)$.
Steps to Solve
- Identify the inequalities
Start with the given inequalities. For example, let's say we have two inequalities:
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$y > 2x + 1$
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$y \leq -x + 4$
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Graph the first inequality
To graph $y > 2x + 1$, first start by graphing the line $y = 2x + 1$. This line has a slope of 2 and a y-intercept of 1.
- Draw a dashed line since the inequality is “greater than” (not including the line).
- Next, shade the area above the line to indicate that we're interested in points where $y$ is greater than $2x + 1$.
- Graph the second inequality
Now graph the second inequality $y \leq -x + 4$.
- Start by graphing the line $y = -x + 4$. This line has a slope of -1 and a y-intercept of 4.
- This time, draw a solid line because the inequality includes equality (less than or equal to).
- Shade the area below this line to show that we're focused on points where $y$ is less than or equal to $-x + 4$.
- Identify the feasible region
The feasible region is the area where the shaded areas from both inequalities overlap. This is the solution to the system of inequalities.
- Check a point within the feasible region
Choose a point within the shaded overlap area to determine if it satisfies both inequalities. For example, you might choose the point (0, 3).
- Check it against both inequalities:
- For $y > 2x + 1$: $3 > 2(0) + 1$ (True)
- For $y \leq -x + 4$: $3 \leq -(0) + 4$ (True)
Since the point satisfies both inequalities, it is a valid solution.
A coordinate point that satisfies both inequalities could be $(0, 3)$.
More Information
This solution demonstrates how to graphically solve a system of inequalities and identify a point that meets both conditions. The concept of shading regions based on inequalities leads to a feasible region where solutions exist.
Tips
- Graphing a solid line for inequalities that should be dashed (or vice versa).
- Shading the incorrect region of the graph.
- Not checking if the chosen point satisfies both inequalities.
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