Number of moles of MnO4- getting reduced to Mn2+ under acidic condition by 4.517 x 10^24 electrons is:

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Understand the Problem

The question is asking for the number of moles of MnO4- that are reduced to Mn2+ under acidic conditions when a specific number of electrons (4.517 x 10^24) are involved. This requires understanding the relationship between moles of electrons and moles of the compound in a redox reaction.

Answer

The number of moles of $\text{MnO}_4^-$ reduced to $\text{Mn}^{2+}$ is $1.5 \text{ moles}$.
Answer for screen readers

The number of moles of $\text{MnO}_4^-$ getting reduced to $\text{Mn}^{2+}$ is $1.5 \text{ moles}$.

Steps to Solve

  1. Determine the charge transfer in the reaction

    In the reduction of permanganate ion ($\text{MnO}_4^-$) to manganese ion ($\text{Mn}^{2+}$) under acidic conditions, the reaction involves the transfer of 5 electrons per mole of $\text{MnO}_4^-$.

  2. Calculate the number of moles of electrons

    Given the total number of electrons is $4.517 \times 10^{24}$, we use Avogadro's number (approximately $6.022 \times 10^{23}$) to convert electrons to moles:

    $$ \text{moles of electrons} = \frac{4.517 \times 10^{24} \text{ electrons}}{6.022 \times 10^{23} \text{ electrons/mole}} $$

    Calculating the above gives:

    $$ \text{moles of electrons} \approx 7.48 \text{ moles} $$

  3. Determine the number of moles of MnO4- reduced

    Since 5 moles of electrons are required for every mole of $\text{MnO}_4^-$ reduced,

    $$ \text{moles of } \text{MnO}_4^- = \frac{7.48 \text{ moles of electrons}}{5 \text{ moles of electrons/mole of } \text{MnO}_4^-} $$

    Performing this calculation gives:

    $$ \text{moles of } \text{MnO}_4^- \approx 1.496 \text{ moles} $$

  4. Round the result

    Since we want the final answer in whole or half moles, we round $1.496 \text{ moles}$ to $1.5 \text{ moles}$.

The number of moles of $\text{MnO}_4^-$ getting reduced to $\text{Mn}^{2+}$ is $1.5 \text{ moles}$.

More Information

The reduction of permanganate ion to manganese ion is a common reaction in redox chemistry, particularly in analytical chemistry for titrations. The stoichiometry must be carefully understood to make accurate calculations of reactants and products.

Tips

Common mistakes include:

  • Not using the correct number of moles of electrons required per mole of $\text{MnO}_4^-$ (which is 5).
  • Failing to correctly convert between number of electrons and moles using Avogadro's number.

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