Jacob needs at least $240 to purchase a new skateboard. He has already saved $60. He plans to walk dogs in the neighborhood to make the rest of the money. He charges $15 per dog. W... Jacob needs at least $240 to purchase a new skateboard. He has already saved $60. He plans to walk dogs in the neighborhood to make the rest of the money. He charges $15 per dog. What is the fewest number of dogs he will have to walk to save enough money to buy the skateboard?

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Understand the Problem

The question is asking how many dogs Jacob needs to walk in order to save enough money to buy a skateboard. He already has $60 and needs at least $240, and he earns $15 for each dog walked. We need to determine the minimum number of dogs he must walk to reach that goal.

Answer

The fewest number of dogs Jacob must walk is \( x \geq 12 \).
Answer for screen readers

The fewest number of dogs Jacob must walk is ( x \geq 12 ).

Steps to Solve

  1. Determine the total amount needed.

Jacob needs at least $240 for the skateboard. He already has $60 saved.

Total amount needed: $$ 240 - 60 = 180 $$

  1. Calculate the earnings per dog walked.

Jacob earns $15 for each dog he walks.

  1. Set up the equation for the number of dogs he needs to walk.

Let ( x ) be the number of dogs he needs to walk. The money earned from walking dogs can be represented as: $$ 15x $$

  1. Set up the inequality based on the total amount needed.

We need to ensure that the money earned is at least $180, so we can set up the inequality: $$ 15x \geq 180 $$

  1. Solve for ( x ).

To find ( x ), divide both sides by 15: $$ x \geq \frac{180}{15} $$

This simplifies to: $$ x \geq 12 $$

The fewest number of dogs Jacob must walk is ( x \geq 12 ).

More Information

Jacob needs to walk at least 12 dogs to have enough money for the skateboard. If he walks 12 dogs, he will earn $180, bringing his total to $240.

Tips

  • Miscalculating the total amount needed by not subtracting the amount he already has.
  • Forgetting to set up the inequality correctly based on earnings.

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