If x satisfies the equation 48^x = 256, then x is equal to _____.

Question image

Understand the Problem

The question is asking to solve for x in the equation 48^x = 256. This will likely involve logarithmic properties to isolate x.

Answer

The value of \(x\) is equal to \( log_4 8 \).
Answer for screen readers

The value of (x) simplifies to (\frac{8}{4 + \frac{\log(3)}{\log(2)}}), which we can approximate or compare with the choices given.

Steps to Solve

  1. Apply logarithms to both sides

Take the logarithm of both sides of the equation (48^x = 256). You can use any logarithm base, but common logarithms (base 10) or natural logarithms (base (e)) are typically used.

$$ \log(48^x) = \log(256) $$

  1. Use the power rule of logarithms

Utilize the power rule, which states that (\log(a^b) = b \cdot \log(a)).

$$ x \cdot \log(48) = \log(256) $$

  1. Isolate x

Now, solve for (x) by dividing both sides by (\log(48)).

$$ x = \frac{\log(256)}{\log(48)} $$

  1. Simplify ( \log(256) )

Recognize that (256 = 2^8), so:

$$ \log(256) = 8 \cdot \log(2) $$

  1. Simplify ( \log(48) )

Express (48) in terms of its prime factors:

$$ 48 = 16 \cdot 3 = 2^4 \cdot 3 $$

Thus,

$$ \log(48) = \log(2^4) + \log(3) = 4 \cdot \log(2) + \log(3) $$

  1. Substitute back to find x

Substituting these into the equation for (x):

$$ x = \frac{8 \cdot \log(2)}{4 \cdot \log(2) + \log(3)} $$

  1. Further simplification

This can be somewhat simplified, but for the sake of matching options, we'll evaluate what this means numerically or in relation to the answer choices.

The value of (x) simplifies to (\frac{8}{4 + \frac{\log(3)}{\log(2)}}), which we can approximate or compare with the choices given.

More Information

The answer requires simplifying logarithmic expressions to find a valid representation among the provided options.

Tips

  • Not applying the power rule correctly.
  • Forgetting to consider the properties of logarithms when simplifying.
  • Not expressing numbers in their exponential forms (like (256) as (2^8)) can complicate calculations.

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