If the sum of 7 consecutive numbers is 140, which number is the smallest?
Understand the Problem
The question is asking for the smallest number in a set of 7 consecutive integers whose sum equals 140. To find the smallest number, we can denote the smallest number as 'x'. Therefore, the consecutive numbers can be represented as x, x+1, x+2, x+3, x+4, x+5, x+6. We can set up the equation x + (x+1) + (x+2) + (x+3) + (x+4) + (x+5) + (x+6) = 140 and solve for x.
Answer
$17$
Answer for screen readers
The smallest number in the set of 7 consecutive integers is $17$.
Steps to Solve
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Set up the equation for the sum of the integers
We need to sum the 7 consecutive integers represented as $x, x+1, x+2, x+3, x+4, x+5, x+6$. This can be expressed mathematically as: $$ x + (x+1) + (x+2) + (x+3) + (x+4) + (x+5) + (x+6) = 140 $$ -
Simplify the left side of the equation
Combine like terms on the left side: $$ 7x + (0 + 1 + 2 + 3 + 4 + 5 + 6) = 140 $$ The sum of the numbers $0 + 1 + 2 + 3 + 4 + 5 + 6$ equals $21$, so we rewrite the equation as: $$ 7x + 21 = 140 $$ -
Isolate the variable
Subtract $21$ from both sides to isolate the term with $x$: $$ 7x = 140 - 21 $$ This simplifies to: $$ 7x = 119 $$ -
Solve for x
Now, divide both sides by $7$: $$ x = \frac{119}{7} $$ This simplifies to: $$ x = 17 $$ -
Answer verification
Finally, we can check our answer by finding the consecutive integers: $17, 18, 19, 20, 21, 22, 23$. We add them up to ensure they equal $140$: $$ 17 + 18 + 19 + 20 + 21 + 22 + 23 = 140 $$ This confirms our solution.
The smallest number in the set of 7 consecutive integers is $17$.
More Information
This problem demonstrates the properties of consecutive integers and how to set up and solve a simple algebraic equation. The sum of a series of numbers can help illustrate the concept of averages and number series.
Tips
- Failing to combine like terms correctly in the equation can lead to an incorrect final result.
- Not checking the solution by summing the consecutive integers to ensure they match the original total.
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