If log_8 (60) - log_8 (3) - log_8 (5) is to be simplified using the properties of logarithms, what would be the resultant expression?
Understand the Problem
The question is asking to simplify the expression using properties of logarithms. Specifically, we will use the property that states the difference of logarithms can be expressed as the logarithm of a quotient: log_a(b) - log_a(c) = log_a(b/c). In this case, we will simplify the expression log_8(60) - log_8(3) - log_8(5) step by step.
Answer
$\frac{2}{3}$
Answer for screen readers
The simplified expression is $\frac{2}{3}$.
Steps to Solve
- Identify the logarithmic property to use
We will use the property of logarithms that states $ \log_a(b) - \log_a(c) = \log_a\left(\frac{b}{c}\right)$.
- Apply the property to the first two logarithms
Using the property, we can simplify the first part of the expression:
$$ \log_8(60) - \log_8(3) = \log_8\left(\frac{60}{3}\right) $$
- Calculate the quotient
We calculate the quotient:
$$ \frac{60}{3} = 20 $$
So, we have:
$$ \log_8(60) - \log_8(3) = \log_8(20) $$
- Combine with the remaining logarithm
Now we apply the logarithmic property again with the next logarithm $\log_8(5)$:
$$ \log_8(20) - \log_8(5) = \log_8\left(\frac{20}{5}\right) $$
- Calculate the final quotient
Next, we calculate:
$$ \frac{20}{5} = 4 $$
Thus, we have:
$$ \log_8(20) - \log_8(5) = \log_8(4) $$
- Final simplification
We now recognize that $4 = 8^{2/3}$, so we can express the final result as:
$$ \log_8(4) = \log_8(8^{2/3}) = \frac{2}{3} $$
The simplified expression is $\frac{2}{3}$.
More Information
In this problem, we utilized the properties of logarithms to combine several logarithmic expressions into a single logarithm. The final result demonstrates the power of logarithmic simplification, which is helpful in various mathematical contexts, including calculus and exponential equations.
Tips
- Forgetting to apply the logarithmic property correctly when combining logarithms.
- Miscalculating quotients when simplifying logarithmic expressions. Always double-check your arithmetic!
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