If log_8 (60) - log_8 (3) - log_8 (5) is to be simplified using the properties of logarithms, what would be the resultant expression?

Understand the Problem

The question is asking to simplify the expression using properties of logarithms. Specifically, we will use the property that states the difference of logarithms can be expressed as the logarithm of a quotient: log_a(b) - log_a(c) = log_a(b/c). In this case, we will simplify the expression log_8(60) - log_8(3) - log_8(5) step by step.

Answer

$\frac{2}{3}$
Answer for screen readers

The simplified expression is $\frac{2}{3}$.

Steps to Solve

  1. Identify the logarithmic property to use

We will use the property of logarithms that states $ \log_a(b) - \log_a(c) = \log_a\left(\frac{b}{c}\right)$.

  1. Apply the property to the first two logarithms

Using the property, we can simplify the first part of the expression:

$$ \log_8(60) - \log_8(3) = \log_8\left(\frac{60}{3}\right) $$

  1. Calculate the quotient

We calculate the quotient:

$$ \frac{60}{3} = 20 $$

So, we have:

$$ \log_8(60) - \log_8(3) = \log_8(20) $$

  1. Combine with the remaining logarithm

Now we apply the logarithmic property again with the next logarithm $\log_8(5)$:

$$ \log_8(20) - \log_8(5) = \log_8\left(\frac{20}{5}\right) $$

  1. Calculate the final quotient

Next, we calculate:

$$ \frac{20}{5} = 4 $$

Thus, we have:

$$ \log_8(20) - \log_8(5) = \log_8(4) $$

  1. Final simplification

We now recognize that $4 = 8^{2/3}$, so we can express the final result as:

$$ \log_8(4) = \log_8(8^{2/3}) = \frac{2}{3} $$

The simplified expression is $\frac{2}{3}$.

More Information

In this problem, we utilized the properties of logarithms to combine several logarithmic expressions into a single logarithm. The final result demonstrates the power of logarithmic simplification, which is helpful in various mathematical contexts, including calculus and exponential equations.

Tips

  • Forgetting to apply the logarithmic property correctly when combining logarithms.
  • Miscalculating quotients when simplifying logarithmic expressions. Always double-check your arithmetic!

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