Given the vectors AB = (7, -2) and BC = (-3, 5), work out how much further Pru travels than Yang when Pru travels from A to B and then B to C, and Yang travels directly from A to C... Given the vectors AB = (7, -2) and BC = (-3, 5), work out how much further Pru travels than Yang when Pru travels from A to B and then B to C, and Yang travels directly from A to C. Provide your answer in km, correct to one decimal place.

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Understand the Problem

The question is asking us to calculate the distance that Pru travels compared to Yang by using vector values provided for the segments of the triangle. Pru travels from A to B and then from B to C, while Yang travels directly from A to C. We need to determine how much further Pru travels than Yang and give the answer in kilometers, rounded to one decimal place.

Answer

$8.1 \text{ km}$
Answer for screen readers

The difference in the distance traveled by Pru compared to Yang is approximately $8.1 \text{ km}$.

Steps to Solve

  1. Calculate the distance Pru travels (AB + BC)

Pru travels from A to B and then from B to C. To find the total distance, we first need to calculate the individual distances.

For segment $AB$, represented as vector $\overrightarrow{AB} = (7, -2)$:

  • The distance from $A$ to $B$ can be found using the formula for the magnitude of a vector: $$ |AB| = \sqrt{(7)^2 + (-2)^2} $$

Calculating this gives: $$ |AB| = \sqrt{49 + 4} = \sqrt{53} \approx 7.28 \text{ km} $$

Now for segment $BC$, represented as vector $\overrightarrow{BC} = (-3, 5)$:

  • The distance from $B$ to $C$ is calculated similarly: $$ |BC| = \sqrt{(-3)^2 + (5)^2} $$

Calculating this gives: $$ |BC| = \sqrt{9 + 25} = \sqrt{34} \approx 5.83 \text{ km} $$

Now, adding both distances for Pru's total distance: $$ \text{Total distance (Pru)} = |AB| + |BC| = \sqrt{53} + \sqrt{34} \approx 7.28 + 5.83 \approx 13.11 \text{ km} $$

  1. Calculate the distance Yang travels (AC)

Yang travels directly from A to C. We need to determine the vector $\overrightarrow{AC}$ which can be found by adding vectors $\overrightarrow{AB}$ and $\overrightarrow{BC}$: $$ \overrightarrow{AC} = \overrightarrow{AB} + \overrightarrow{BC} = (7, -2) + (-3, 5) = (7 - 3, -2 + 5) = (4, 3) $$

Next, we calculate the distance from $A$ to $C$: $$ |AC| = \sqrt{(4)^2 + (3)^2} $$

Calculating gives: $$ |AC| = \sqrt{16 + 9} = \sqrt{25} = 5 \text{ km} $$

  1. Calculate the difference in distance traveled

Now, we can find out how much further Pru travels compared to Yang: $$ \text{Difference} = \text{Total distance (Pru)} - |AC| $$

Substituting the values gives: $$ \text{Difference} = 13.11 - 5 = 8.11 \text{ km} $$

Thus, rounding the answer to one decimal place: $$ \text{Difference} \approx 8.1 \text{ km} $$

The difference in the distance traveled by Pru compared to Yang is approximately $8.1 \text{ km}$.

More Information

Pru's journey is longer since she travels along two segments of the triangle, while Yang takes the direct path. Understanding vector components and applying the distance formula is essential for such calculations in geometry.

Tips

  • Confusing the addition of vector components when calculating the resultant vector.
  • Misapplying the distance formula or forgetting to take the square root of the sum of squares.
  • Overlooking the rounding requirement for the final answer.

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