For the generalized structure BrCH2CHClCH2CHClCH2Cl there exists what number of stereoisomers?
Understand the Problem
The question is inquiring about the number of stereoisomers for a specified chemical structure, which involves understanding the concepts of stereoisomerism in organic chemistry.
Answer
The number of stereoisomers is $4$.
Answer for screen readers
There are 4 stereoisomers for the structure BrCH₂CHClCH₂CHClCH₂Cl.
Steps to Solve
- Identify Chiral Centers
First, we need to identify the chiral centers in the molecule. A chiral center is typically a carbon atom attached to four different groups.
- Count the Chiral Centers
In the structure BrCH₂CHClCH₂CHClCH₂Cl:
- The carbon atoms can be numbered:
- C1: CH₂Br
- C2: CHCl
- C3: CH₂
- C4: CHCl
- C5: CH₂Cl
Assessing these gives:
- C2 and C4 are chiral centers because they each have different substituents (Cl, H, and the carbon chains).
- Calculate the Number of Stereoisomers
The formula for calculating the number of stereoisomers is given by:
$$ S = 2^n $$
where $n$ is the number of chiral centers.
In this case, we have 2 chiral centers:
$$ S = 2^2 = 4 $$
- Conclusion
Thus, the final step is to conclude that there are 4 stereoisomers based on the identified chiral centers.
There are 4 stereoisomers for the structure BrCH₂CHClCH₂CHClCH₂Cl.
More Information
Stereoisomers are compounds with the same molecular formula and connectivity but differ in the spatial arrangement of atoms. The presence of chiral centers significantly increases the complexity and number of possible isomers.
Tips
- Overlooking Chiral Centers: Ensure all potential chiral centers are identified.
- Incorrect Application of the Formula: Remember to apply the formula $S = 2^n$ correctly, using the total number of chiral centers.
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