Find the values of x and y.
Understand the Problem
The question is asking to find the values of x and y in a right triangle where one angle is 30 degrees and the opposite side is 9. It involves applying trigonometric principles to solve for the unknown sides.
Answer
$x = \frac{9\sqrt{3}}{2}, \; y = 18$
Answer for screen readers
The values are ( x = \frac{9\sqrt{3}}{2} ) and ( y = 18 ).
Steps to Solve
- Identify the triangle properties
The triangle is a right triangle with one angle measuring $30^\circ$. The side opposite the $30^\circ$ angle is given as $9$.
- Using the sine function for side ( y )
In a right triangle, the sine of an angle is the ratio of the length of the opposite side to the hypotenuse. We can use: $$ \sin(30^\circ) = \frac{\text{opposite}}{\text{hypotenuse}} $$ Thus, $$ \sin(30^\circ) = \frac{9}{y} $$
Since ( \sin(30^\circ) = \frac{1}{2} ), we have: $$ \frac{1}{2} = \frac{9}{y} $$
- Solve for ( y )
Multiply both sides by ( y ) and then by ( 2 ): $$ y = 18 $$
- Using the cosine function for side ( x )
Now we can use the cosine function for the angle to find side ( x ): $$ \cos(30^\circ) = \frac{\text{adjacent}}{\text{hypotenuse}} $$ This translates to: $$ \cos(30^\circ) = \frac{x}{9} $$
- Solve for ( x )
Since ( \cos(30^\circ) = \frac{\sqrt{3}}{2} ), we have: $$ \frac{\sqrt{3}}{2} = \frac{x}{9} $$
Multiply both sides by ( 9 ): $$ x = 9 \cdot \frac{\sqrt{3}}{2} $$ Thus, $$ x = \frac{9\sqrt{3}}{2} $$
The values are ( x = \frac{9\sqrt{3}}{2} ) and ( y = 18 ).
More Information
In a 30-60-90 triangle, the ratios of the lengths of the sides are ( 1 : \sqrt{3} : 2 ). This means that the side opposite the ( 30^\circ ) angle is half the length of the hypotenuse.
Tips
- Misapplying the sine or cosine functions by not correctly identifying the opposite and adjacent sides relative to the given angle.
- Forgetting to use the correct ratios for a 30-60-90 triangle can lead to incorrect side lengths.
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