Complete the table by converting the 8-bit binary number '11110000' into denary, and the denary number '105' into 8-bit binary, and convert '00011110' into denary.
Understand the Problem
The question is asking to fill in a table by converting between binary and denary (decimal) numbers. Specifically, it requires converting the 8-bit binary number '11110000' into its denary equivalent, and converting the denary number '105' into its 8-bit binary equivalent, as well as converting '00011110' into denary.
Answer
- 240 (for $11110000$), - $01101001$ (for $105$), - 30 (for $00011110$).
Answer for screen readers
- Denary equivalent of $11110000$: $240$
- 8-bit binary equivalent of $105$: $01101001$
- Denary equivalent of $00011110$: $30$
Steps to Solve
- Convert Binary to Denary (11110000)
To convert the binary number $11110000$ to denary, we multiply each bit by $2^n$, where $n$ is the position of the bit from the right (starting from $0$).
Calculating each bit:
- $1 \times 2^7 = 128$
- $1 \times 2^6 = 64$
- $1 \times 2^5 = 32$
- $1 \times 2^4 = 16$
- $0 \times 2^3 = 0$
- $0 \times 2^2 = 0$
- $0 \times 2^1 = 0$
- $0 \times 2^0 = 0$
Now, sum them up: $$ 128 + 64 + 32 + 16 + 0 + 0 + 0 + 0 = 240 $$
- Convert Denary to Binary (105)
To convert the denary number $105$ into binary, we repeatedly divide by $2$ and note the remainders.
- $105 \div 2 = 52$ with a remainder of $1$
- $52 \div 2 = 26$ with a remainder of $0$
- $26 \div 2 = 13$ with a remainder of $0$
- $13 \div 2 = 6$ with a remainder of $1$
- $6 \div 2 = 3$ with a remainder of $0$
- $3 \div 2 = 1$ with a remainder of $1$
- $1 \div 2 = 0$ with a remainder of $1$
Now, reading the remainders from bottom to top gives the binary representation: $$ 1101001 $$
To ensure it is an 8-bit representation, add leading zeros: $$ 01101001 $$
- Convert Binary to Denary (00011110)
To convert the binary number $00011110$ to denary, we again multiply each bit by $2^n$.
Calculating each bit:
- $0 \times 2^7 = 0$
- $0 \times 2^6 = 0$
- $0 \times 2^5 = 0$
- $1 \times 2^4 = 16$
- $1 \times 2^3 = 8$
- $1 \times 2^2 = 4$
- $1 \times 2^1 = 2$
- $0 \times 2^0 = 0$
Now, sum them up: $$ 0 + 0 + 0 + 16 + 8 + 4 + 2 + 0 = 30 $$
- Denary equivalent of $11110000$: $240$
- 8-bit binary equivalent of $105$: $01101001$
- Denary equivalent of $00011110$: $30$
More Information
The conversions between binary and denary systems are essential in computer science, as data is often represented in binary form while being processed and manipulated in decimal form.
Tips
- Forgetting to sum all the products in binary to denary conversion.
- Not accounting for leading zeros when converting denary to an 8-bit binary representation.
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