Calculate the malasity of the human genome in relation to the diameter of the nucleus in one mm.

Steps to Solve

1. Define Malasity
   Before we can calculate anything, we need to clarify what "malasity" means in this context. Since it is not a recognized term in genetics, we might assume it refers to some aspect of genetic density or quantity in relation to the size of the nucleus.

2. Understand the size of the human genome
   The human genome consists of approximately 3 billion base pairs. We will express this in terms of physical units measurable against a nuclear dimension.

3. Estimate the volume of a nucleus
   A nucleus is roughly spherical with a diameter of 1 millimeter. We can find its volume using the formula for the volume of a sphere: $$ V = \frac{4}{3} \pi r^3 $$ where the radius $ r = \frac{d}{2} = \frac{1 \text{ mm}}{2} = 0.5 \text{ mm} = 0.05 \text{ cm} $.

4. Calculate the volume
   Now, we plug in the radius into the formula: $$ V = \frac{4}{3} \pi (0.05 \text{ cm})^3 $$ $$ V \approx \frac{4}{3} \pi (0.000125 \text{ cm}^3) $$ $$ V \approx 5.24 \times 10^{-4} \text{ cm}^3. $$

5. Determine density of the genome
   To relate the human genome (3 billion base pairs) to the volume of a nucleus, we need the "density" or packing factor: $$ \text{Density} = \frac{\text{Number of base pairs}}{\text{Volume of nucleus}} = \frac{3 \times 10^9 \text{ base pairs}}{5.24 \times 10^{-4} \text{ cm}^3} $$

6. Final calculation
   Now we compute the density: $$ \text{Density} \approx \frac{3 \times 10^9}{5.24 \times 10^{-4}} \text{ base pairs/cm}^3 $$ $$ \text{Density} \approx 5.73 \times 10^{12} \text{ base pairs/cm}^3. $$