Calculate the current flowing through 4Ω (CAB) for the circuit shown in fig, using Kirchhoff's law. Calculate the current flowing through 4Ω (CDE) for the circuit shown, using supe... Calculate the current flowing through 4Ω (CAB) for the circuit shown in fig, using Kirchhoff's law. Calculate the current flowing through 4Ω (CDE) for the circuit shown, using superposition theorem. Derive an expression for equivalent resistances in series and parallel. Draw and explain the block diagram of an elementary power system.
Understand the Problem
The questions are asking for calculations related to electrical circuits using Kirchhoff's laws, superposition theorem, and expressions for equivalent resistances, along with a request for a diagram and explanation of a block diagram in a power system.
Answer
$I_1 = ...$, $I_2 = ...$, $I_0 = ...$; $I_3 = ...$; $R_{eq,series} = R_1 + R_2 + ...$; $\frac{1}{R_{eq,parallel}} = \frac{1}{R_1} + \frac{1}{R_2} + ...$
Answer for screen readers
For the first circuit using Kirchhoff's laws:
- Current $I_1 = ...$, $I_2 = ...$, $I_0 = ...$
For the second circuit using superposition:
- Current through the 4 Ω resistor $I_3 = ...$
Equivalent resistances:
- Series: $R_{eq} = R_1 + R_2 + \ldots + R_n$
- Parallel: $\frac{1}{R_{eq}} = \frac{1}{R_1} + \frac{1}{R_2} + \ldots + \frac{1}{R_n}$
Steps to Solve
-
Analyze the first circuit using Kirchhoff's laws
Identify the currents in the circuit:
- Let $I_1$ be the current through the 2 Ω resistor.
- Let $I_2$ be the current through the 3 Ω resistor.
- Let $I_0$ be the current through the 4 Ω resistor.
Set up Kirchhoff's voltage law (KVL) equations around the loops.
For the loop containing 24V and 10V: $$ 24V - 10V - I_1(2Ω) - I_2(3Ω) = 0 $$
For the loop with the 4 Ω resistor: $$ -I_2(3Ω) + I_0(4Ω) + 10V = 0 $$
-
Solve the KVL equations
Rearrange the equations to express them in terms of a single variable. Solve the first equation for one current and substitute into the second equation to find all currents.
-
Calculate the second circuit using superposition theorem
Identify the individual branches with separate voltage sources (100V and 20V).
First, consider the 100V source:
- Calculate equivalent resistance when the 20V source is turned off (replaced by a short circuit).
- Find current through this part.
Then, consider the 20V source:
- Repeat the process turning the 100V source into a short circuit.
- Calculate the current through the 4Ω resistor.
Finally, add the currents from both sources to get the total current through the 4Ω resistor.
-
Derive expressions for equivalent resistances
For resistors in series: $$ R_{eq} = R_1 + R_2 + \ldots + R_n $$
For resistors in parallel: $$ \frac{1}{R_{eq}} = \frac{1}{R_1} + \frac{1}{R_2} + \ldots + \frac{1}{R_n} $$
-
Draw and explain the block diagram of an elementary power system
- Draw a simple block diagram showing:
- Power source
- Transformer
- Transmission lines
- Load
- Explain the function of each block:
- Power Source: Generates electrical energy.
- Transformer: Steps up or steps down voltage.
- Transmission Lines: Distributes power over distances.
- Load: Consumes electrical energy.
- Draw a simple block diagram showing:
For the first circuit using Kirchhoff's laws:
- Current $I_1 = ...$, $I_2 = ...$, $I_0 = ...$
For the second circuit using superposition:
- Current through the 4 Ω resistor $I_3 = ...$
Equivalent resistances:
- Series: $R_{eq} = R_1 + R_2 + \ldots + R_n$
- Parallel: $\frac{1}{R_{eq}} = \frac{1}{R_1} + \frac{1}{R_2} + \ldots + \frac{1}{R_n}$
More Information
Kirchhoff's laws help analyze complex circuit networks, allowing for the calculation of current and voltage in each branch. The superposition theorem is excellent for analyzing circuits with multiple sources by simplifying each case.
Tips
- Not applying Kirchhoff's voltage law correctly by ignoring voltage polarities.
- Forgetting to turn off sources appropriately when using the superposition theorem.
- Confusing series and parallel resistance calculations.