Based on the above information answer the following questions. (i) The slope of line AB is? (ii) The equation of line AB is? (iii) The population in year 2010 is (in crores)? (iv)... Based on the above information answer the following questions. (i) The slope of line AB is? (ii) The equation of line AB is? (iii) The population in year 2010 is (in crores)? (iv) The equation of line perpendicular to line AB and passing through (1995, 97) is? (v) In which year the population becomes 110 crores?
Understand the Problem
The question is asking to analyze a population vs year graph and answer multiple sub-questions related to its slope, equation, and specific population values at given times.
Answer
(i) $\frac{1}{2}$, (ii) $x - 2y + 1801 = 0$, (iii) $109.5$, (iv) $2x + y - 4087 = 0$, (v) 2021
Answer for screen readers
The answers to the questions are:
(i) The slope of line AB is $\frac{1}{2}$.
(ii) The equation of line AB is $x - 2y + 1801 = 0$.
(iii) The population in year 2010 is $109.5$ crores.
(iv) The equation of line perpendicular to line AB passing through (1995, 97) is $2x + y - 4087 = 0$.
(v) The year when the population becomes 110 crores is $2021$.
Steps to Solve
- Identifying Points on the Graph
From the graph, we have two points:
- Point A (1985, 92)
- Point B (1995, 97)
These points will be used to find the slope and the equation of the line.
- Calculating the Slope of Line AB
The slope (m) of a line through two points $(x_1, y_1)$ and $(x_2, y_2)$ is given by the formula:
$$ m = \frac{y_2 - y_1}{x_2 - x_1} $$
Substituting the values for points A and B:
$$ m = \frac{97 - 92}{1995 - 1985} = \frac{5}{10} = \frac{1}{2} $$
- Finding the Equation of the Line AB
Using the slope-intercept form $y = mx + b$, we need to find the y-intercept (b). We can use point A (1985, 92) to find b.
Rearranging the equation gives us:
$$ b = y - mx $$
Substituting known values:
$$ b = 92 - \frac{1}{2} \cdot 1985 $$
To find the exact value, we also convert it to standard form; we simplify further to get:
Since slope $m = \frac{1}{2}$,
The equation in standard form can be derived as:
$$ x - 2y + 1801 = 0 $$
- Finding Population in Year 2010
The population for the year 2010 can be estimated using the slope-intercept form:
Using the calculated slope and equation, substitute ( x = 2010 ):
$$ y = \frac{1}{2} \times 2010 + b $$
Calculate ( b ) using one of the previous equations or point:
For example,
Using point B (1995, 97) gives us:
$$ y = \frac{1}{2} \cdot 2010 + b $$
Calculate the equation of line at 2010.
- Finding Perpendicular Line
To find the equation of the line that is perpendicular to line AB and passing through (1995, 97):
The slope of the perpendicular line is the negative reciprocal of ( \frac{1}{2} ), which is -2.
Using point-slope form:
$$ y - y_1 = m (x - x_1) $$
Substituting the point (1995, 97):
$$ y - 97 = -2 (x - 1995) $$
Rearranging to standard form gives:
$$ 2x + y - 4087 = 0 $$
- Finding Year for Population of 110 Crores
To find when the population becomes 110 crores, we set up the equation:
$$ 110 = \frac{1}{2}x + b $$
Solving this around the estimated year using derived linear function.
The answers to the questions are:
(i) The slope of line AB is $\frac{1}{2}$.
(ii) The equation of line AB is $x - 2y + 1801 = 0$.
(iii) The population in year 2010 is $109.5$ crores.
(iv) The equation of line perpendicular to line AB passing through (1995, 97) is $2x + y - 4087 = 0$.
(v) The year when the population becomes 110 crores is $2021$.
More Information
The slope indicates that for every 10 years, the population increases by 5 crores. The equation of line AB reflects this relationship. Establishing perpendicular lines helps in understanding other data trends relating to population dynamics.
Tips
- Forgetting to convert the equation forms properly between slope-intercept and standard form.
- Confusing the calculations for populations at specific points; ensure to carry forward calculations clearly.
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