A famous relation in physics relates moving mass m to the rest mass mo of a particle in terms of its speed v and the speed of light, c. A boy recalls the relation almost correctly... A famous relation in physics relates moving mass m to the rest mass mo of a particle in terms of its speed v and the speed of light, c. A boy recalls the relation almost correctly but forgets where to put the constant c. He writes: m/mo = (1 - v^2/c^2)^(1/2). Guess where to put the missing c.
Understand the Problem
The question is asking to identify the correct placement of the speed of light constant c in the equation relating moving mass m to rest mass mo based on the principles of special relativity.
Answer
m = m0 / (1 - v^2/c^2)^(1/2).
The relation is m = m0 / (1 - v^2/c^2)^(1/2).
Answer for screen readers
The relation is m = m0 / (1 - v^2/c^2)^(1/2).
More Information
This relation is derived from Einstein's theory of special relativity, where 'moving mass' is affected by its velocity relative to the speed of light.
Tips
A common mistake is placing the constant c incorrectly. Ensure that "c^2" is in the denominator.
Sources
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