A compound whose molecular weight is 40, prepare its 10% solution.
Understand the Problem
The question is asking how to prepare a 10% solution of a compound with a molecular weight of 40. This involves calculating the amount of the compound needed to create a solution of a specified volume while achieving the desired concentration.
Answer
You need 100 grams of the compound to prepare a 10% solution in 1 liter.
Answer for screen readers
To prepare a 10% solution in 1 liter of total volume, you need 100 grams of the compound.
Steps to Solve
- Determine the target volume of the solution
Let's assume you want to prepare 1 liter (1000 mL) of a 10% solution.
- Calculate the mass of the compound needed
To make a 10% solution, you need 10 grams of solute for every 100 mL of solution. Since your target volume is 1000 mL, you calculate the mass needed:
$$ \text{Mass} = \left( \frac{10 \text{ g}}{100 \text{ mL}} \right) \times 1000 \text{ mL} $$
- Perform the multiplication
Now perform the calculation:
$$ \text{Mass} = \frac{10 \times 1000}{100} = 100 \text{ g} $$
- Final step: Prepare the solution
Weigh out 100 grams of the compound and dissolve it in enough solvent (usually water) to reach a total volume of 1 liter.
To prepare a 10% solution in 1 liter of total volume, you need 100 grams of the compound.
More Information
A 10% solution means there are 10 grams of solute per 100 mL of solution, which can be useful for various laboratory preparations and experiments.
Tips
- Not understanding the definition of percentage concentration and mixing up grams with mL.
- Forgetting to account for the total volume of the solution when measuring the solute.
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