2D + D + 1 = sin(2x)
Understand the Problem
The question is asking to solve the equation 2D + D + 1 = sin(2x) for the variable D in terms of x. This involves understanding both algebraic manipulation and trigonometric functions.
Answer
$$ D = \frac{\sin(2x)  1}{3} $$
Answer for screen readers
The value of $D$ in terms of $x$ is $$ D = \frac{\sin(2x)  1}{3} $$
Steps to Solve
 Combine Like Terms First, we combine the terms involving $D$ on the left side of the equation: $$ 2D + D = 3D $$
Now, the equation becomes: $$ 3D + 1 = \sin(2x) $$

Isolate the Term with D Next, we need to isolate the term with $D$. We do this by subtracting 1 from both sides: $$ 3D = \sin(2x)  1 $$

Solve for D Now, we solve for $D$ by dividing both sides by 3: $$ D = \frac{\sin(2x)  1}{3} $$
The value of $D$ in terms of $x$ is $$ D = \frac{\sin(2x)  1}{3} $$
More Information
The solution shows that $D$ is expressed as a function of the trigonometric sine function. This relationship is useful in various fields, such as physics and engineering, where wave functions often appear.
Tips
 Forgetting to combine like terms before isolating the variable. Always check to group similar terms when possible to simplify the equation.
 Not moving all terms to one side of the equation when isolating the variable. It's important to follow proper algebraic rules to ensure accuracy.