1. Find the rank of the matrix by Echelon form method. 2. Show that X1 = (1, -1, 1), X2 = (2, 1, 1), X3 = (1, 2, 2) are linearly dependent. 3. Test the consistency of the following... 1. Find the rank of the matrix by Echelon form method. 2. Show that X1 = (1, -1, 1), X2 = (2, 1, 1), X3 = (1, 2, 2) are linearly dependent. 3. Test the consistency of the following system of linear equations: 2x - y + 3z = 8, -x + 2y + z = 4, 3x + y - 4z = 0 and solve them. 4. Find the eigenvalues and corresponding eigenvectors for the matrix A = [[1, -6, -4], [0, 4, 2], [0, -6, -3]]. 5. Express (1,1,2) as a linear combination of vectors (0,2,1), (2,2,4) in V3(R). 6. Define the following: (i) Linear Transformation, (ii) Basis and dimension, (iii) Subspace, (iv) Kernel of transformation.

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Understand the Problem

The questions presented involve solving mathematical problems related to linear algebra. This includes finding the rank of a matrix, determining linear dependency among vectors, testing the consistency of a system of linear equations, finding eigenvalues and eigenvectors, and expressing a vector as a linear combination of others. Additionally, definitions related to linear transformations and concepts from linear algebra are requested.

Answer

Answer for screen readers
  1. Rank of the matrix: 3

  2. The vectors ( X_1, X_2,

Steps to Solve

  1. Finding the Rank of the Matrix To find the rank of the matrix

$$ \begin{bmatrix} 2 & 4 & 3 & -2 \ -3 & -2 & -1 & 4 \ 6 & -1 & 7 & 2 \end{bmatrix} $$

we will use the Echelon form method.

  1. Transform the Matrix Perform row operations to transform the matrix into an upper triangular form.
  • Start with the original matrix:

$$ \begin{bmatrix} 2 & 4 & 3 & -2 \ -3 & -2 & -1 & 4 \ 6 & -1 & 7 & 2 \end{bmatrix} $$

  • Replace Row 2 with ( R_2 + \frac{3}{2}R_1 ) and Row 3 with ( R_3 - 3R_1 ):

$$ \begin{bmatrix} 2 & 4 & 3 & -2 \ 0 & 4 & 3.5 & 2 \ 0 & -13 & -2.5 & 8 \end{bmatrix} $$

  • Next, simplify further by performing more row operations to eliminate below the first pivot.
  1. Continue to Row Echelon Form Perform ( R_3 = R_3 + \frac{13}{4}R_2 ):

$$ \begin{bmatrix} 2 & 4 & 3 & -2 \ 0 & 4 & 3.5 & 2 \ 0 & 0 & 7.125 & 9.5 \end{bmatrix} $$

From here, we can conclude that the non-zero rows give us the rank.

  1. Count the Non-zero Rows The matrix in row echelon form has 3 non-zero rows, so the rank is:

$$ \text{Rank}(A) = 3 $$

  1. Show Linear Dependency of Vectors To show that

$$ \mathbf{X_1} = (1, -1, 1), \quad \mathbf{X_2} = (2, 1, 1), \quad \mathbf{X_3} = (1, 2, 2) $$

are linearly dependent, we need to find scalars ( a, b, c ) such that:

$$ a\mathbf{X_1} + b\mathbf{X_2} + c\mathbf{X_3} = 0 $$

By setting this up in matrix form and solving for ( a, b, c ), we can determine dependencies.

  1. Testing Consistency of the System of Linear Equations Set up the augmented matrix for the equations:

$$ \begin{cases} 2x - y + 3z = 8 \ -x + 2y + z = 4 \ 3x + y - 4z = 0 \end{cases} $$

Use row reduction to find if a solution exists.

  1. Finding Eigenvalues and Eigenvectors For the matrix

$$ A = \begin{bmatrix} 1 & -6 & -4 \ 0 & 4 & 2 \ 0 & -6 & -3 \end{bmatrix} $$

Find the characteristic polynomial by calculating ( \det(A - \lambda I) ) and solve for ( \lambda ).

  1. Express as Linear Combination To express ( (1, 1, 2) ) as a linear combination of ( (0, 2, 1) ) and ( (2, 2, 4) ), you set:

$$ c_1(0, 2, 1) + c_2(2, 2, 4) = (1, 1, 2) $$

and solve for ( c_1, c_2 ).

  1. Define the Concepts
  • Linear Transformation: A function between two vector spaces that preserves the operations of vector addition and scalar multiplication.
  • Basis and Dimension: A basis of a vector space is a set of linearly independent vectors that spans the space; the dimension is the number of vectors in a basis.
  • Subspace: A subset of a vector space that is itself a vector space under the same operations.
  • Kernel of Transformation: The set of vectors that are mapped to the zero vector by a linear transformation.
  1. Rank of the matrix: 3

  2. The vectors ( X_1, X_2,

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