Ideal Gas Law Quiz
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Ideal Gas Law Quiz

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@FragrantSpessartine

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Questions and Answers

Match the following quantities with their corresponding values in the context of the ideal gas law solution:

Pressure (P) = 1.0 atm Volume (V) = 1.0 L Temperature (T) = 293.15 K Gas constant (R) = 0.082 L atm mol−1 K−1

Match the following terms with their definitions in relation to the calculation of oxygen mass in air:

Mole fraction (x) = Proportion of oxygen in the mixture (0.22) Molecular mass of O2 = 32 g mol−1 Ideal gas behavior = Assumption for calculations Moles of O2 (n) = 0.00924 mol

Match the following calculations to their corresponding results during the exercise:

n = PV/RT = 0.042 mol n(O2) = x(O2) x n = 0.00924 mol Mass O2 = n(O2) x Molecular mass = 0.296 g Temperature conversion = 293.15 K

Match the parameters with their corresponding ideal gas law values:

<p>P (Pressure) = 1.0 atm R (Gas constant) = 0.082 L atm mol−1 K−1 V (Volume) = 1.0 L T (Temperature in K) = 293.15 K</p> Signup and view all the answers

Match the following aspects of the tutorial with their respective importance in the solution:

<p>Molecular mass of O2 = Key for calculating mass Mole fraction (x(O2)) = Indicates proportion of oxygen Ideal gas behavior = Rationale for using PV = nRT Temperature conversion = Necessary for calculations in Kelvin</p> Signup and view all the answers

Study Notes

Ideal Gas Law

  • The ideal gas law equation is PV = nRT
  • Where:
    • P is pressure in atmospheres (atm)
    • V is volume in liters (L)
    • n is the number of moles
    • R is the ideal gas constant (0.082 L atm mol−1 K−1)
    • T is temperature in Kelvin (K)
  • To find the number of moles, n, rearrange the equation to n= PV/RT

Converting Temperatures

  • To convert from Celsius to Kelvin, add 273.15 to the Celsius temperature
  • 20°C is equal to 293.15 K

Calculating Number of Moles

  • The number of moles of air can be calculated using the equation n = PV/RT
  • Using the values given:
    • P = 1.0 atm
    • V = 1.0 L
    • R = 0.082 L atm mol−1 K−1
    • T = 293.15 K
  • The number of moles of air is 0.042 mol

Mole Fraction

  • The mole fraction of a component in a mixture is the ratio of the number of moles of that component to the total number of moles
  • The mole fraction of oxygen (O2) in air is 0.22
  • Therefore, the number of moles of oxygen in 1.0 L of air is 0.22 x 0.042 mol = 0.00924 mol

Calculating Mass of Oxygen

  • The molecular mass of oxygen (O2) is 32 g mol−1
  • The mass of oxygen in 1 L of air is 32 g mol−1 x 0.00924 mol = 0.296 g

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Description

Test your understanding of the Ideal Gas Law with this quiz. It covers the equation PV = nRT, temperature conversions, and the calculation of the number of moles. Challenge your knowledge on mole fractions and air composition as well.

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