Field Effect Transistor (FET) Basics
10 Questions
0 Views

Choose a study mode

Play Quiz
Study Flashcards
Spaced Repetition
Chat to lesson

Podcast

Play an AI-generated podcast conversation about this lesson

Questions and Answers

What is a potential consequence of operating a JFET beyond its breakdown voltage?

  • The device will experience irreversible damage (correct)
  • The device will enter a state of constant current
  • The device will operate more efficiently
  • The device will produce a higher output voltage
  • What is the purpose of operating a JFET below breakdown and within the constant-current area?

  • To increase the device's current handling capacity
  • To increase the device's output voltage
  • To reduce the device's power consumption
  • To prevent irreversible damage to the device (correct)
  • What is the effect of increasingly negative values of VGS on the drain current ID?

  • ID becomes unpredictable
  • ID remains constant
  • ID increases
  • ID decreases (correct)
  • What happens to the JFET when VGS is set to a sufficiently large negative value?

    <p>ID is reduced to zero</p> Signup and view all the answers

    What is the relationship between VGS and the pinch-off point in a JFET?

    <p>The pinch-off point occurs at a lower VDS for more negative VGS</p> Signup and view all the answers

    What is the effect of VGS on the channel width in a JFET?

    <p>The channel width decreases as VGS becomes more negative</p> Signup and view all the answers

    What is the role of VGG in a JFET?

    <p>VGG is used to adjust VGS</p> Signup and view all the answers

    What is the characteristic of the drain characteristic curves in a JFET?

    <p>They are a family of curves that vary with VGS</p> Signup and view all the answers

    What is the region of operation where the JFET produces a constant current?

    <p>The constant-current region</p> Signup and view all the answers

    What is the relationship between VGS and ID in the active region?

    <p>ID decreases as VGS becomes more negative</p> Signup and view all the answers

    Study Notes

    Field Effect Transistor (FET)

    • "Field effect" relates to the depletion region formed in the channel of a FET when voltage is applied on one of its terminals (gate).

    Types of FETs

    • Two main types of FETs are:
      • Junction Field Effect Transistor (JFET)
      • Metal Oxide Semiconductor Field Effect Transistor (MOSFET)

    JFET

    • JFET has two channel types:
      • n channel
      • p channel

    JFET Structures and Symbols

    • JFET structures and symbols are represented in a diagram.

    Basic Operation of JFET

    • VDD provides a drain-to-source voltage and supplies current from drain to source.
    • VGG sets the reverse-bias voltage between gate and source.
    • JFET is always operated with the gate-source pn junction reverse biased.
    • Reverse-bias of gate-source junction with negative gate voltage produces a depletion region along pn junction, increasing resistance by restricting the channel width.
    • Greater VGG narrows the channel, increasing the resistance of the channel and decreasing ID.
    • Less VGG widens the channel, decreasing the resistance of the channel and increasing ID.
    • The channel width and resistance can be controlled by varying the gate voltage, controlling the amount of drain current, ID.

    Drain Characteristic

    • JFET with VGS=0 V and variable VDS (VDD) shows a drain characteristic curve.
    • Pinch-off occurs where constant current begins.

    JFET Characteristic, VGS = 0

    • As VDD (and thus VDS) is increased from 0V, ID will increase proportionally in the ohmic region.
    • In this area, the channel resistance is essentially constant because of the depletion region.
    • IG = 0, an important characteristic for JFET.
    • At point B, the curve levels off and enters the active region where ID is constant.
    • The value of VDS at which ID becomes constant is the pinch-off voltage, VP.
    • As VDD increases from point B to point C, the reverse-bias voltage from gate to drain produces a depletion region large enough to offset the increase in VDS, keeping ID relatively constant.

    VGS = 0

    • VDS increases above VP, produce almost constant ID called IDSS.
    • IDSS (drain to source current with gate shorted) is the maximum drain current at VGS = 0V.
    • Breakdown occurs at point C when ID begins to increase very rapidly with any further increase in VDS, which can result in irreversible damage to the device.
    • JFETs are always operated below breakdown and within the constant-current area.

    VGS Controls ID

    • As VGS is set to increasingly more negative values by adjusting VGG, a family of drain characteristic curves is produced.
    • ID decreases as the magnitude of VGS is increased to larger negative values because of the narrowing of the channel.
    • For each increase in VGS, the JFET reaches pinch-off at values of VDS less than VP.

    JFET at Cutoff

    • The more negative VGS is, the smaller ID becomes in the active region.
    • When VGS has a sufficiently large negative value, ID is reduced to zero.

    Studying That Suits You

    Use AI to generate personalized quizzes and flashcards to suit your learning preferences.

    Quiz Team

    Description

    Understanding the fundamentals of Field Effect Transistors, including the depletion region formation and its relation to voltage application.

    More Like This

    MOSFET Field Effect Transistor (FET)
    20 questions
    Field-Effect Transistors (FET)
    10 questions
    FET Transistor Basics
    10 questions
    Use Quizgecko on...
    Browser
    Browser