Biochemistry Equilibrium Constant (Keq) Quiz
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Questions and Answers

What does the equilibrium constant Keq represent in the isomerisation of glucose-6-phosphate to fructose-6-phosphate?

  • The amount of time required to reach equilibrium.
  • The temperature at which isomerisation occurs.
  • The rate at which glucose-6-phosphate converts to fructose-6-phosphate.
  • The ratio of the concentrations of reactants to products at equilibrium. (correct)

    • If the initial concentration of glucose-6-phosphate (G6P) is 0.1 M and the equilibrium constant Keq is 0.428, what can be inferred about the relationship between [G6P] and [F6P] at equilibrium?

  • There will be equal amounts of G6P and F6P created from the reaction.
  • There will be more G6P than F6P at equilibrium. (correct)
  • The concentration of G6P will equal the concentration of F6P at equilibrium.
  • The concentration of F6P will exceed the concentration of G6P at equilibrium.

    • How would you calculate the concentration of fructose-6-phosphate (F6P) at equilibrium given Keq = 0.428 and an initial concentration of 0.1 M for glucose-6-phosphate (G6P)?

  • Use the formula $Keq = [G6P] + [F6P]$ to find [F6P].
  • Calculate [F6P] using $Keq = \frac{[G6P]}{[F6P]}$.
  • Use the formula $Keq = \frac{[F6P]}{[G6P]}$ and solve for [F6P]. (correct)
  • Assume that [F6P] is equal to the initial concentration of G6P.

    • In the context of the isomerisation reaction between glucose-6-phosphate and fructose-6-phosphate, what does a Keq value of 0.428 suggest about the extent of the reaction at equilibrium?

    <p>The reaction favors the reactant G6P, indicating a lower concentration of product F6P at equilibrium.</p> Signup and view all the answers

    What is a necessary condition for the isomerisation of glucose-6-phosphate to fructose-6-phosphate regarding the concentrations of the substances involved?

    <p>Both G6P and F6P must be present at equilibrium.</p> Signup and view all the answers

    Study Notes

    Equilibrium Constant (Keq)

    • Keq is the ratio of product concentrations to reactant concentrations at equilibrium.
    • At 25°C, the Keq for the isomerisation of glucose-6-phosphate (G6P) to fructose-6-phosphate (F6P) is 0.428.
    • This means that at equilibrium, the concentration of F6P is 0.428 times the concentration of G6P.

    Calculating [F6P] at Equilibrium

    • If the initial concentration of G6P is 0.1 M, then at equilibrium, the concentration of F6P can be calculated using the Keq value.
    • Since F6P is formed from G6P, the concentration of F6P at equilibrium will be less than the initial concentration of G6P.

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    Description

    Test your understanding of the equilibrium constant (Keq) in biochemistry. This quiz covers the concepts related to the isomerization of glucose-6-phosphate to fructose-6-phosphate and calculating equilibrium concentrations. Practice using Keq values to solve real-world biochemical problems.

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