Equilibrium Constant in Biochemistry

The equilibrium constant Keq for the isomerisation of glucose-6-phosphate (G6P) to fructose-6-phosphate (F6P) at 25 ◦C is ______.

At equilibrium, the concentration of F6P can be calculated if the initial concentration of G6P is ______ M.

F6P molecules can only be formed from ______ molecules.

The process being referred to is the isomerisation of glucose-6-phosphate to ______.

The temperature at which the equilibrium constant is defined is ______ °C.

Equilibrium Constant

The equilibrium constant (Keq) for the isomerization of glucose-6-phosphate (G6P) to fructose-6-phosphate (F6P) at 25°C is 0.428.
Keq is a measure of the ratio of products to reactants at equilibrium.
For the isomerization of G6P to F6P, Keq is defined as:
- Keq = [F6P]/[G6P] at equilibrium.
This indicates that at equilibrium, the concentration of F6P is less than the concentration of G6P.

Equilibrium Concentration

At 25°C, the initial concentration of G6P is 0.1 M.
The concentration of F6P at equilibrium can be calculated using the Keq value and the initial concentration of G6P.
Since F6P molecules are formed from G6P molecules.
We can set up an ICE table to solve for the equilibrium concentrations.
- Initial: [G6P] = 0.1 M, [F6P] = 0 M
- Change: -x, +x
- Equilibrium: 0.1 - x, x
Plugging these values into the Keq equation:
- 0.428 = x / (0.1 - x)
- Solving for x, we get x = [F6P] at equilibrium = 0.030 M.
The concentration of F6P at equilibrium at 25°C is 0.030 M.

This quiz explores the concept of equilibrium constants, particularly focusing on the isomerization of glucose-6-phosphate to fructose-6-phosphate at 25°C. Participants will learn to calculate equilibrium concentrations using an ICE table and understand the significance of the equilibrium constant (Keq).