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Questions and Answers
The equilibrium constant Keq for the isomerisation of glucose-6-phosphate (G6P) to fructose-6-phosphate (F6P) at 25 ◦C is ______.
0.428
At equilibrium, the concentration of F6P can be calculated if the initial concentration of G6P is ______ M.
0.1
F6P molecules can only be formed from ______ molecules.
G6P
The process being referred to is the isomerisation of glucose-6-phosphate to ______.
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The temperature at which the equilibrium constant is defined is ______ °C.
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Study Notes
Equilibrium Constant
- The equilibrium constant (Keq) for the isomerization of glucose-6-phosphate (G6P) to fructose-6-phosphate (F6P) at 25°C is 0.428.
- Keq is a measure of the ratio of products to reactants at equilibrium.
- For the isomerization of G6P to F6P, Keq is defined as:
- Keq = [F6P]/[G6P] at equilibrium.
- This indicates that at equilibrium, the concentration of F6P is less than the concentration of G6P.
Equilibrium Concentration
- At 25°C, the initial concentration of G6P is 0.1 M.
- The concentration of F6P at equilibrium can be calculated using the Keq value and the initial concentration of G6P.
- Since F6P molecules are formed from G6P molecules.
- We can set up an ICE table to solve for the equilibrium concentrations.
- Initial: [G6P] = 0.1 M, [F6P] = 0 M
- Change: -x, +x
- Equilibrium: 0.1 - x, x
- Plugging these values into the Keq equation:
- 0.428 = x / (0.1 - x)
- Solving for x, we get x = [F6P] at equilibrium = 0.030 M.
- The concentration of F6P at equilibrium at 25°C is 0.030 M.
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Description
This quiz explores the concept of equilibrium constants, particularly focusing on the isomerization of glucose-6-phosphate to fructose-6-phosphate at 25°C. Participants will learn to calculate equilibrium concentrations using an ICE table and understand the significance of the equilibrium constant (Keq).
