Linear Algebra (BAS012) Lecture Notes PDF

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Sphinx University

Dr.Amira A.Allam

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linear algebra complex numbers mathematics university lecture

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This document is a lecture note for a linear algebra course (BAS012) at Sphinx University. The note covers the basic concepts of complex numbers including definitions, operations on complex numbers, conjugate of complex numbers, and associated properties. Exercises for practice are also included.

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LINEAR ALGEBRA (BAS012) SPHINX UNIVERSITY Dr.Amira A.Allam [email protected] Practical Information Lectures 12 lectures (2 hours) Tutorials 9 sheets (2 hours) Readings Stewart, J. (2015) Calculus, Brooks/Cole Publishing Company,....

LINEAR ALGEBRA (BAS012) SPHINX UNIVERSITY Dr.Amira A.Allam [email protected] Practical Information Lectures 12 lectures (2 hours) Tutorials 9 sheets (2 hours) Readings Stewart, J. (2015) Calculus, Brooks/Cole Publishing Company,.8th edition. Briggs, Cochran and Gillett (2015), Calculus, Pearson; 2nd edition. Syllabus Complex Numbers Synthetic division and the roots (Numerical root finder) Binomial series mathematical induction vector spaces Matrices (Gauss elimination method - inverse of a nonsingular - eigenvalues and eigenvectors – transformation matrices) Assessment System 40% Final exam 30% Mid-term exam Semester work 20% Quiz 10% Tutorial Important Remarks  Lectures notes are available, while white board is an essential element of this course.  Take notes in the lectures (just copy the white board).  Attempt all homework problems.  Review the material before each exam  textbook  Lectures notes  Model answer of the homework problems Lecture 1  Complex numbers  operations on Complex numbers  conjugate of Complex numbers Complex numbers Definition: A complex number 𝑧 is an ordered pair of real numbers 𝑎, 𝑏 : a is called Real part of 𝑧, denoted by 𝑅𝑒 𝑧 and 𝑏 is called imaginary part of 𝑧, denoted by 𝐼𝑚 𝑧. If 𝑅𝑒 𝑧 = 0, then z is called purely imaginary If 𝐼𝑚 𝑧 = 0, then z is called real. 𝐶 is the set of all complex numbers. Complex numbers operations of addition and multiplication over the set C of all complex numbers (𝑎, 𝑏) = (𝑐, 𝑑) if and only if 𝑎 = 𝑐 𝑎𝑛𝑑 𝑏 = 𝑑, (𝑎, 𝑏) + (𝑐, 𝑑) = (𝑎 + 𝑐, 𝑏 + 𝑑), (𝑎, 𝑏). (𝑐, 𝑑) = (𝑎𝑐 − 𝑏𝑑, 𝑎𝑑 + 𝑏𝑐) operations on Complex numbers The set 𝐶 of all complex numbers under the operations of addition and multiplication as defined above satisfies following properties: for 𝑧1 , 𝑧2 , 𝑧3 ∈ 𝐶, 1) 𝑧1 + 𝑧2 = 𝑧2 + 𝑧1 (commutatively). 2) (𝑧1 + 𝑧2 ) + 𝑧3 = 𝑧1 + (𝑧2 + 𝑧3 ) (associativity), 3) 𝑧1 + (0,0) = 𝑧1 (existence of identity), 4) for 𝑧 = (𝑎, 𝑏) ∈ 𝐶, there exists – 𝑧 = (−𝑎, −𝑏) ∈ 𝐶 such that (−𝑧) + 𝑧 = 𝑧 + (−𝑧) = (0,0) (existence of inverse), operations on Complex numbers for 𝑧1 , 𝑧2 , 𝑧3 ∈ 𝐶, 1) 𝑧1. 𝑧2 = 𝑧2. 𝑧1 (commutatively). 2) 𝑧1. 𝑧2. 𝑧3 = 𝑧1. (𝑧2. 𝑧3 ) (associativity), 3) 𝑧1. (1,0) = 𝑧1 (existence of identity), 1 4) for 𝑧 = (𝑎, 𝑏) ∈ 𝐶, and 𝑧 ≠ (0,0) there exists ∈ 𝐶 such that 𝑧 1 1. 𝑧 = 𝑧. = 1 (existence of inverse), 𝑧 𝑧 operations on Complex numbers Denoting the complex number (0,1) by 𝑖 and identifying a real complex number (𝑎, 0) with the real number 𝑎, we see 𝑧 = (𝑎, 𝑏) = (𝑎, 0) + (0, 𝑏) = (𝑎, 0) + (0,1)(𝑏, 0) can be written 𝑎𝑠 𝑧 = 𝑎 + 𝑖𝑏. For two real numbers 𝑎, 𝑏 , 𝑎2 + 𝑏 2 = 0 implies 𝑎 = 0 = 𝑏, but in complex numbers not the same, for example 12 + 𝑖 2 = 0 but 1 ≡ (1,0) ≠ (0,0) ≡ 0 𝑎𝑛𝑑 𝑖 = (0,1) ≠ 0,0. 𝑖 2 = (0,1)(0,1) = (−1,0) ≡ −1. Conjugate of Complex numbers Let 𝑧 = (𝑥, 𝑦) ≡ 𝑥 + 𝑖𝑦. The conjugate of 𝑧, denoted by 𝑧 , is (𝑥, −𝑦) ≡ 𝑥 − 𝑖𝑦. Conjugate of Complex numbers Geometrically, the point (representing) 𝑧 is the reflection of the point (representing) 𝑧 in the real axis. The conjugation operation satisfies the following properties: 𝑧=𝑧 𝑧1 + 𝑧2 = 𝑧1 + 𝑧2 𝑧 𝑧1 ( 1) = 𝑧2 𝑧2 𝑧 + 𝑧 = 2 𝑅𝑒 𝑧, 𝑧 − 𝑧 = 2𝑖 𝐼𝑚(𝑧) Exercises Write down the imaginary part of the complex number 3 + 4𝑖 − 6(2 + 8𝑖). Answer: Exercises Write down the imaginary part of the complex number 3 + 4𝑖 − 6(2 + 8𝑖). Answer: 𝐼𝑚*3 + 4𝑖 − 6(2 + 8𝑖)+ = 𝐼𝑚*3 − 12 + (4 − 48)𝑖+ = 4 − 48 = −44 Exercises Solve the equation 𝑥 2 + 4𝑥 + 9 = 0 simplifying your answers as far as possible. Answer: Exercises Solve the equation 𝑥 2 + 4𝑥 + 9 = 0 simplifying your answers as far as possible. Answer: (𝑥 + 2)2 −4 + 9 = 0 ⇒ (𝑥 + 2)2 = −5 ⇒ 𝑥 = −2 ± 𝑖 5 Exercises Solve the equation 16𝑥 4 = 625. Answer: 625 625 𝑥4 = 4 ⇒𝑥 − =0 16 16 2 25 2 25 ⇒ (𝑥 − )(𝑥 + ) = 0 4 4 5 5 5 5 ⇒ (𝑥 − )(𝑥 + )(𝑥 + 𝑖)(𝑥 − 𝑖) = 0 2 2 2 2 5 5 ⇒ 𝑥 = ± 𝑜𝑟 ± 𝑖 2 2

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