Some Basic Concept NEET RPS-03 Solutions PDF
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Summary
This document is a set of solutions for a chemistry past paper designated for NEET (National Eligibility cum Entrance Test). The problems cover a range of basic chemical concepts, providing a useful study resource for students preparing for this important exam.
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SOME BASIC CONCEPT-RPS-03 1. Ans: (c) No. of molecules left = 2.73 × 1021 – 1021 CaCO3 → CaCO + CO2 (↑) = 1.73 × 1021 1 mole of CaCO3 gives 1 mole of CaO…...
SOME BASIC CONCEPT-RPS-03 1. Ans: (c) No. of molecules left = 2.73 × 1021 – 1021 CaCO3 → CaCO + CO2 (↑) = 1.73 × 1021 1 mole of CaCO3 gives 1 mole of CaO… 1.73 1021 No. of moles = = 2.88 10−3 6.23 1023 1 mole of CaCO3 = 100 g of CaCO3 10. Ans: (a) 1 mole of CaO = (40 +16)g = 56 g of CaO 11. Ans; (b) 2. Ans: (2) 12. Ans: (c) 3. Ans: (c) % Atomic Simple Element Mole Ratio 4. Ans: (d) Composition Mass Ratio 38.71 3.22 C 38.71 12 = 3.22 =1 5. Ans: (a) 12 3.22 9.67 9.67 H 9.67 1 = 9.67 =3 6. Ans: (b) 1 3.22 100 – (38.71 51.62 3.22 O + 9.67) = 16 = 3.22 =1 7. Ans: (a) 16 3.22 51.62 8. Ans: (a) E.F = MO 9. Ans: (a) 13. Ans: (b) 14. Ans: (b) 0.2 1 Number of moles = = 44 220 N=M×n number of molecules Number of moles = = 0.0521 × 3 Avogadro's number = 0.1563 N Number of molecules = Avogadro’s number × number of moles 15. Ans: (a) No. of molecules = 6.022 × 1023 × 1 1 = 2.73 1021 Molecules in moles 220 220 As 1021 molecules are removed,
