Ray Optics JEE Main 2024 January Question Bank PDF

Ray Optics JEE Main 2024 January Question Bank Questions with Answer Keys MathonGo Q1 - 2024 (01 Feb Shift 1) The distance between ob...

Ray Optics JEE Main 2024 January Question Bank Questions with Answer Keys MathonGo Q1 - 2024 (01 Feb Shift 1) The distance between object and its 3 times magnified virtual image as produced by a convex lens is 20 cm. The focal length of the lens used is_____ cm. Q2 - 2024 (27 Jan Shift 1) If the refractive index of the material of a prism is cot( A 2 ) , where A is the angle of prism then the angle of minimum deviation will be (1) π − 2 A (2) π 2 − 2 A (3) π − A (4) π 2 − A Q3 - 2024 (27 Jan Shift 1) A convex lens of focal length 40 cm forms an image of an extended source of light on a photoelectric cell. A current I is produced. The lens is replaced by another convex lens having the same diameter but focal length 20 cm. The photoelectric current now is : (1) I 2 (2) 4 I (3) 2 I (4) I Q4 - 2024 (27 Jan Shift 1) Two immiscible liquids of refractive indices 8 5 and 3 2 respectively are put in a beaker as shown in the figure. The height of each column is 6 cm. A coin is placed at the bottom of the beaker. For near normal vision, the Do you want to practice these PYQs along with PYQs of JEE Main from 2002 till 2024? Click here to download MARKS App Ray Optics JEE Main 2024 January Question Bank Questions with Answer Keys MathonGo apparent depth of the coin is α 4 cm. The value of α is _____. Q5 - 2024 (29 Jan Shift 1) A convex mirror of radius of curvature 30 cm forms an image that is half the size of the object. The object distance is : (1) −15 cm (2) 45 cm (3) −45 cm (4) 15 cm Q6 - 2024 (29 Jan Shift 1) A biconvex lens of refractive index 1.5 has a focal length of 20 cm in air. Its focal length when immersed in a liquid of refractive index 1.6 will be: (1) −16 cm (2) −160 cm (3) +160 cm (4) +16 cm Q7 - 2024 (29 Jan Shift 2) If the distance between object and its two times magnified virtual image produced by a curved mirror is 15 cm, the focal length of the mirror must be : (1) 15 cm (2) −12 cm Do you want to practice these PYQs along with PYQs of JEE Main from 2002 till 2024? Click here to download MARKS App Ray Optics JEE Main 2024 January Question Bank Questions with Answer Keys MathonGo (3) −10 cm (4) 10/3 cm Q8 - 2024 (30 Jan Shift 1) The distance between object and its two times magnified real image as produced by a convex lens is 45 cm. The focal length of the lens used is_____ cm. Q9 - 2024 (30 Jan Shift 2) In an experiment to measure the focal length (f) of a convex lens, the magnitude of object distance (x) and the image distance (y) are measured with reference to the focal point of the lens. The y − x plot is shown in figure. The focal length of the lens is_____cm. Q10 - 2024 (31 Jan Shift 1) The refractive index of a prism with apex angle A is cot A/2. The angle of minimum deviation is : (1) δ m = 180 ∘ − A (2) δ m = 180 ∘ − 3 A (3) δ m = 180 ∘ − 4 A (4) δ m = 180 ∘ − 2 A Q11 - 2024 (31 Jan Shift 2) Do you want to practice these PYQs along with PYQs of JEE Main from 2002 till 2024? Click here to download MARKS App Ray Optics JEE Main 2024 January Question Bank Questions with Answer Keys MathonGo Light from a point source in air falls on a convex curved surface of radius 20 cm and refractive index 1.5. If the source is located at 100 cm from the convex surface, the image will be formed at_____ cm from the object. Do you want to practice these PYQs along with PYQs of JEE Main from 2002 till 2024? Click here to download MARKS App Ray Optics JEE Main 2024 January Question Bank Questions with Answer Keys MathonGo Answer Key Q1 (15) Q2 (1) Q3 (4) Q4 (31) Q5 (1) Q6 (2) Q7 (3) Q8 (10) Q9 (20) Q10 (4) Q11 (200) Do you want to practice these PYQs along with PYQs of JEE Main from 2002 till 2024? Click here to download MARKS App Ray Optics JEE Main 2024 January Question Bank Solutions MathonGo Q1 v = 3u v − u = 20 cm 2u = 20 cm u = 10 cm 1 1 1 − = (−30) (−10) f f = 15 cm Q2 A+δmin sin( ) A 2 cot = A 2 sin 2 A A + δmin ⇒ cos = sin( ) 2 2 A + δmin π A = − 2 2 2 δmin = π − 2 A Q3 As amount of energy incident on cell is same so current will remain same. Q4 h1 h2 6 6 15 31 hupp = + = + = 4 + = cm μ1 μ2 3/2 8/5 4 4 Q5 Do you want to practice these PYQs along with PYQs of JEE Main from 2002 till 2024? Click here to download MARKS App Ray Optics JEE Main 2024 January Question Bank Solutions MathonGo Given R = 30 cm f = R/2 = +15 cm Magnification (m) = ± 1 2 For convex mirror, virtual image is formed for real object. Therefore, m is +ve 1 f = 2 f − u u = −15 cm Q6 μ1 = 1.5 μm = 1.6 fa = 20 cm fm (μ1 − 1) μm As = fa (μ1 − μm ) fm (1.5 − 1)1.6 = 20 (1.5 − 1.6) fm = −160 cm Q7 Do you want to practice these PYQs along with PYQs of JEE Main from 2002 till 2024? Click here to download MARKS App Ray Optics JEE Main 2024 January Question Bank Solutions MathonGo −v m = 2 = u −(15 − u) 2 = −u 2u = 15 − u 3u = 15 ⇒ u = 5 cm v = 15 − u = 15 − 5 = 10 cm 1 1 1 = + f v u 1 1 1 − 2 −1 = + = = 10 (−5) 10 10 f = −10 cm Q8 v = −2 u v = −2u...(i) v − u = 45...(ii) ⇒ u = −15 cm v = 30 cm 1 1 1 = − f v u f = +10 cm Q9 1 1 1 − = f + 20 −(f + 20) f 2 1 = f = 20 cm f + 20 f 2 Or x1 x2 = f gives f = 20 cm Q10 Do you want to practice these PYQs along with PYQs of JEE Main from 2002 till 2024? Click here to download MARKS App Ray Optics JEE Main 2024 January Question Bank Solutions MathonGo A+δm sin( ) 2 μ = A sin 2 A+δm A cos sin( ) 2 2 = A A sin sin 2 2 π A A + δm sin( − ) = sin( ) 2 2 2 π A A δm − = + 2 2 2 2 δm = π − 2A Q11 μ2 μ1 μ2 − μ1 − = v u R 1.5 1 1.5 − 1 − = v −100 20 v = 100 cm Distance from object = 100 + 100 = 200 cm Do you want to practice these PYQs along with PYQs of JEE Main from 2002 till 2024? Click here to download MARKS App