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DeliciousCoralReef6316

Uploaded by DeliciousCoralReef6316

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2024

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geometry similarity of triangles theorems mathematics

Summary

This document is a collection of geometry class notes focused on the topic of triangle similarity. It covers different theorems and asks students to prove the similarity of various triangles. The notes are organized into different sections with diagrams that illustrate the concepts.

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# Similarity of triangles ## Geometry 2024 ### Class ## In the opposite figure: AE and BC are two intersecting chords at D in a circle where D is the midpoint of BC * **Prove that:** * **1** AADC~A BDE * **2** (BD)$^2$ = AD × DE > ![A circle with two intersecting chords](./assets/img...

# Similarity of triangles ## Geometry 2024 ### Class ## In the opposite figure: AE and BC are two intersecting chords at D in a circle where D is the midpoint of BC * **Prove that:** * **1** AADC~A BDE * **2** (BD)$^2$ = AD × DE > ![A circle with two intersecting chords](./assets/img/Circle_with_chords.png) ## In the opposite figure: DEO is a triangle, m (∠O) = m (∠DXY), DX = YO = 3 cm. and DY = 5 cm. **Find the length of: XE** > ![A triangle with two intersecting chords](./assets/img/Triangle_with_XO.png) ## Corollary 1 If a line is drawn parallel to one side of a triangle and intersects the other two sides or the lines containing them, then the resulting triangle is similar to the original triangle. **In each of the following figures :** > ![Three triangles with parallel lines](./assets/img/Three_triangles_with_parallel_lines.png) * If DE // BC and intersects AB and AC at D and E respectively, then ∆ABC ~ A ADE ## In the opposite figure : CE ∩ BD = {A}, BC // DE , BC = 5 cm. and DE = 2.5 cm. **1** Prove that: ∆ABC ~ AADE **2** Find the value of : X > ![A triangle with parallel lines](./assets/img/Triangle_with_parallel_lines_2.png) ## Corollary 2 In any right-angled triangle, the altitude to the hypotenuse separates the triangle into two triangles which are similar to each other and to the original triangle. **In the opposite figure :** If ∆ ABC is a right-angled triangle at A and AD ⊥ BC, then A DBA~A DAC ~ ∆ АВС > ![A right-angled triangle with an altitude](./assets/img/Right-angled_triangle_with_altitude.png) * and it is left to the student to prove this corollary by using the previous postulate and its remarks. ## In the opposite figure : ABC is a right-angled triangle at B and BD ⊥ AC If AD = 4.5 cm. and DC = 8cm., **find the values of : X and y** > ![A right-angled triangle with an altitude](./assets/img/Right-angled_triangle_with_altitude_2.png) ## Second case ## Theorem 1 **S.S.S. similarity theorem** If the side lengths of two triangles are in proportion, then the two triangles are similar. **In the opposite figure :** **Prove that:** * **1** The two coloured triangles are similar. * **2** BD bisects ∠ ABE > ![Two coloured triangles](./assets/img/Two_coloured_triangles.png) ## Third case ## Theorem 2 **S.A.S. similarity theorem** If an angle of one triangle is congruent to an angle of another triangle and lengths of the sides including those angles are in proportion, then the triangles are similar. ABC is a triangle in which: AB = 6 cm. and BC = 9 cm. Let D be the midpoint of AB and HEBC such that BH = 2 cm. **Prove that:** * **1** ADBH ~ СВА * **2** ADHC is a cyclic quadrilateral. > ![A triangle with midpoint D](./assets/img/Triangle_with_midpoint_D.png)

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