Module 4 Assessment Quiz Solution PDF - Spring 2022

Document Details

CT Value

Uploaded by CT Value

Santiago Canyon College

2022

Shabbir Basrai

Tags

water treatment wastewater engineering assessment quiz environmental engineering

Summary

This document is an assessment quiz focused on water treatment and wastewater engineering concepts. The quiz includes questions and solutions. The exam covers topics such as the Parshall Flume, weirs, grit removal, and comminution.

Full Transcript

WATR 081 - Spring 2022 Module 4 Assessment Quiz Shabbir Basrai 1. A Parshall Flume is a device used to divide the incoming ow for equal distribution to a plant having more than one primary clarier. a. True b. False 2. A weir can be used as a ow measuring device a. True b. False 3. Inecient gr...

WATR 081 - Spring 2022 Module 4 Assessment Quiz Shabbir Basrai 1. A Parshall Flume is a device used to divide the incoming ow for equal distribution to a plant having more than one primary clarier. a. True b. False 2. A weir can be used as a ow measuring device a. True b. False 3. Inecient grit removal would tend to cause a decrease in percent volatile solids in raw primary sludge a. True b. False 4. Proportional weirs usually are located at: a. A magnetic ow meter b. Stilling wells c. Aerobic digester scum boxes d. Grit chambers e. Water treatment plants 5. The purpose of comminution is to: a. Combine wastewater from dierent sewers prior to entry into the treatment facility. b. Shred large debris and organic material into small particles. c. Liquefy chunks of grease in order to break it down. d. Mix the raw wastewater to distribute the organics. 6. A grit chamber is 2 feet 4 inches wide. When wastewater is owing 8 inches deep in this channel, the ow is found to be 1.6 ft per second. Calculate ow in MGD. Page 1 of 2 Module 4 Assessment Quiz Shabbir Basrai Answers: 1. b. 2. a. 3. a. 4. d. 5. b. 6. A grit chamber is 2 feet 4 inches wide. When wastewater is owing 8 inches deep in this channel, the ow is found to be 1.6 ft per second. Calculate ow in MGD. Solution: Q=V ∗A f t3 f t  28 8  2 ∗ f t = 2.49 Q = 1.6 ∗ s 12 12 s  MG f t3 (1440 ∗ 60)s gal   ∗ 7.48 3 Q = 2.49 ∗ = 1.61M GD  day gal f t  s  Page 2 of 2 WATR 081 - Spring 2022

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