Summary

This document is a maths test focusing on integers, their properties, calculations, and basic algebraic expressions. It contains questions related to finding the greatest common factor (GCF), HCF, and solving equations.

Full Transcript

## Integers and their Properties ### **1. Represent the following nos as integers with appropriate signs:** * (i) A deposit of rupees two thousand. **2000** * (ii) A gain of 50g- **+50** * (iii) A jet plane flying at the height of 2756m. **+2756** ### **2. Solve:** * (i) (47 + 4) + ( - 75) +...

## Integers and their Properties ### **1. Represent the following nos as integers with appropriate signs:** * (i) A deposit of rupees two thousand. **2000** * (ii) A gain of 50g- **+50** * (iii) A jet plane flying at the height of 2756m. **+2756** ### **2. Solve:** * (i) (47 + 4) + ( - 75) + 10 = **26** * (ii) -80 - (21) + 9 = **-92** ### **3. Using appropriate property solve the following:** * (i) 39 X 108 = **108 X 39** * (ii) 52 X 19 + 52 X 30 = **52 X (19 + 30) = 52 X 49** * (iii) 71 X 380 = **380 X 71** ### **4. Fill up** * (i) Integer which is neither positive nor negative. **0** * (ii) -131 is known as **additive inverse** of 131. * (iii) Predecessor of (-7687) is **-7688**. * (iv) Sum of an integer and its additive inverse is always **0**. * (v) Write the integer which is 4 more than -2. **2** ### **6. Find the greatest no. which divides by 12, 16, 18.** * **Answer:** 4 ### **7. Find the least no. which divided 12, 16, 24 and 36 and leave reminder 7 in each case.** * **Answer:** 28 ### **8. Find HCF of:** * (i) 255, 1620, 192 by long division method. * (ii) 144, 180 & 192. * (iii) 48 & 36. ### **9. The literals whose values vary from problem to problem is called** * **Answer:** Variable ### **10. Numerals whose values is fixed is called** * **Answer:** Constant ### **11. Write the expression:** * (i) 4 subtracted from n gives 36. * (ii) Half of n subtracted from the sum of a and p. * (iii) One fourth of the difference of n and s. * (iv) Sum of p, q, r divided by the product of a & b. ### **12. Solve** * (i) 17 - p = 36 - 3p * (ii) 4(2x - 1) - 2(x - 2) = 5(x + 1) + 3 * (iii) 3x = 2(x - 1) - 2 * (iv) 18 - 3y = 11 + y

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